A high school has started a community service program. Under the program, students must participate in volunteer activities, suc
2 answers:
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Answer:
the thermal energy generated in the loop =
Explanation:
Given that;
The length of the copper wire L = 0.614 m
Radius of the loop r =
r =
r = 0.0977 m
However , the area of the loop is :
Change in the magnetic field is
Then the induced emf e =
e =
e = 2.74 × 10⁻³ V
resistivity of the copper wire Ω m
diameter of the wire = 1.08 mm
radius of the wire = 0.54 mm = 0.54 × 10⁻³ m
Thus, the resistance of the wire R =
R =
R = 1.13× 10⁻² Ω
Finally, the thermal energy generated in the loop (i.e the power) =
=
=
(a)
The gravitational potential energy of the two-sphere system is given by
(1)
where
G is the gravitational constant
is the mass of sphere A
is the mass of sphere B
r = 1.8 m is the distance between the two spheres
Substitutign data in the formula, we find
and the sign is negative since gravity is an attractive force.
(b)
According to the law of conservation of energy, the kinetic energy gained by sphere B will be equal to the change in gravitational potential energy of the system:
(2)
where
is the initial potential energy
The final potential energy can be found by substituting
r = 1.80 m -0.60 m=1.20 m
inside the equation (1):
U=-\frac{(6.67\cdot 10^{-11})(94 kg)(100 kg)}{1.2 m}=-5.22\cdot 10^{-7} J
So now we can use eq.(2) to find the kinetic energy of sphere B: