What is the force of a 24.52 kg Television dropped on Pluto (acceleration of 0.59 m/s2)
1 answer:
The force of gravity on the object is 14.47 N
Explanation:
The weight of an object (which is the force of gravity experienced by an object) at a certain location is given by
where
m is the mass of the object
g is the acceleration of gravity at the location of the object
IN this problem, we have:
m = 24.52 kg (mass of the object)
(acceleration of gravity on Pluto)
Substituting, we find the force of gravity on the object:
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Answer:
The angle of elevation of the rocket is increasing at a rate of 48.780º per second.
Explanation:
Geometrically speaking, the distance between the rocket and the observer (), measured in kilometers, can be represented by a right triangle:
(1)
Where:
- Horizontal distance between the rocket and the observer, measured in kilometers.
- Vertical distance between the rocket and the observer, measured in kilometers.
The angle of elevation of the rocket (), measured in sexagesimal degrees, is defined by the following trigonometric relation:
(2)
If we know that , then the expression is:
And the rate of change of this angle is determined by derivatives:
Where:
- Rate of change of the angle of elevation, measured in sexagesimal degrees.
- Vertical speed of the rocket, measured in kilometers per hour.
If we know that and
, then the rate of change of the angle of elevation is:
The angle of elevation of the rocket is increasing at a rate of 48.780º per second.
Answer:
Explanation:
Given that:
angular frequency = 11.3 rad/s
Spring constant (k) =
k = (11.3)² m
k = 127.7 m
where;
= 0.065 m
= 0.048 m
According to the conservation of energies;
∴