What is the force of a 24.52 kg Television dropped on Pluto (acceleration of 0.59 m/s2)
1 answer:
The force of gravity on the object is 14.47 N
Explanation:
The weight of an object (which is the force of gravity experienced by an object) at a certain location is given by
where
m is the mass of the object
g is the acceleration of gravity at the location of the object
IN this problem, we have:
m = 24.52 kg (mass of the object)
(acceleration of gravity on Pluto)
Substituting, we find the force of gravity on the object:
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In electrical circuit, this arrangement is called a R-L series circuit. It is a circuit containing elements of an inductor (L) and a resistor (R). Inductance is expressed in units of Henry while resistance is expressed in units of ohms. The relationship between these values is called the impedance, denoted as Z. Its equation is
Z = √(R^2 + L^2)
Z = √((1.24×10^3 ohms)^2 + (6.95×10^-6 H)^2)
Z = 1,240 ohms
The unit for impedance is also ohms. Since the circuit is in series, the voltage across the inductor and the resistor are additive which is equal to 12 V. Knowing the impedance and the voltage, we can determine the maximum current.
I = V/Z=12/1,240 = 9.68 mA
But since we only want to reach 73.6% of its value, I = 9.68*0.736 = 7.12 mA. Then, the equation for R-L circuits is
, where τ = L/R = 6.95×10^-6/1.24×10^3 = 5.6 x 10^-9
Then,
t = 7.45 nanoseconds
Part B.) If t = 1.00τ, then t/τ = 1. Therefore,
I = 6.12 mA
Z = √(R^2 + L^2)
Z = √((1.24×10^3 ohms)^2 + (6.95×10^-6 H)^2)
Z = 1,240 ohms
The unit for impedance is also ohms. Since the circuit is in series, the voltage across the inductor and the resistor are additive which is equal to 12 V. Knowing the impedance and the voltage, we can determine the maximum current.
I = V/Z=12/1,240 = 9.68 mA
But since we only want to reach 73.6% of its value, I = 9.68*0.736 = 7.12 mA. Then, the equation for R-L circuits is
Then,
t = 7.45 nanoseconds
Part B.) If t = 1.00τ, then t/τ = 1. Therefore,
I = 6.12 mA