1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
andrew11 [14]
3 years ago
13

A total charge of 6.3×10−8 C is distributed uniformly throughout a 2.7-cm radius sphere. The

Physics
2 answers:
Likurg_2 [28]3 years ago
5 0

Answer:

The volume charge density of the sphere is 7.64\times 10^{-4}\ C/m^3.

Explanation:

It is given that,

Charge, q=6.3\times 10^{-8}\ C

Radius of the sphere, r = 2.7 cm = 0.027 m

Total charge contained divided by its volume is called volume charge density. Mathematically, it is given by :

\rho=\dfrac{Q}{V}

\rho=\dfrac{Q}{4/3\pi r^3}

\rho=\dfrac{6.3\times 10^{-8}}{4/3\pi (0.027)^3}

\rho=7.64\times 10^{-4}\ C/m^3

So, the volume charge density of the sphere is 7.64\times 10^{-4}\ C/m^3. Hence, this is the required solution.

stiks02 [169]3 years ago
4 0
The density is 3.7 x 10-7 C/ m3
You might be interested in
Everything is in the pic.
nikitadnepr [17]
The answer is A

Good luck!
3 0
3 years ago
Jada is rowing a boat across a river that has a current of 5 m/s in the ˆ j direction. Leanne, standing on the shore, observes J
olchik [2.2K]

Answer: d. 8.25 m/s

Explanation:

We are given that Current= 5 m/s in j direction

Velocity= 8 m/s i + 3 m/s j

Now, we have to find Jada's speed with respect to the water.

First we find Jada's velocity with respect to water

v= (8 i + 3 j) - (5 j)

v= 8i - 2 j

To find the speed, we take the magnitude of this velocity vector we have

|v|= \sqrt{(8)^2+(-2)^2}

|v|= \sqrt{68} = 8.246 m/s

which comes out to be around = 8.25 m/s

So option d is correct.

5 0
3 years ago
A 0.560 kg snowball is fired from a cliff 14.2 m high with an initial velocity of 13.3 m/s, directed 26.0° above the horizontal.
enot [183]

Answer:

a) v = 21.34 m/s

b) v = 21.34 m/s

c) v = 21.34 m/s

Explanation:

Mass of the snowball, m = 0.560 kg

Height of the cliff, h = 14.2 m

Initial velocity of the ball, u = 13.3 m/s

θ = 26°

The speed of the slow ball as it reaches the ground, v = ?

The initial Kinetic energy of the snow ball, KE_{0}  = 0.5 mu^{2}

Potential energy of the snow ball at the given height, PE = mgh

Final Kinetic energy of the ball as it reaches the ground, KE_{f} = 0.5mv^{2}

a) Using the principle of energy conservation,

KE_{0} + PE = KE_{f} \\0.5mu^{2} + mgh = 0.5mv^{2}\\v^{2} =2( 0.5u^{2} + gh)\\v^{2} =u^{2} + 2gh\\v = \sqrt{u^{2} + 2gh} \\v = \sqrt{13.3^{2} + 2*9.8*14.2}\\v = 21.34 m/s

b) The speed remains v = 21.34 m/s since it is not a function of the angle of launch

c)The principle of energy conservation used cancels out the mass of the object, therefore the speed is not dependent on mass

v = 21. 34 m/s

7 0
4 years ago
An object has a kinetic energy of 175 J and a momentum of magnitude 25.0 kg m/s. Find the
DedPeter [7]

Answer:14 m/s

Explanation:

Kinetic energy(ke)=175J

Momentum(M)=25kgm/s

Speed=v

Mass=m

Ke=(m x v x v)/2

175=(mv^2)/2

Cross multiply

175 x 2=mv^2

350=mv^2

Momentum=mass x velocity

25=mv

m=25/v

Substitute m=25/v in 350=mv^2

350=25/v x v^2

350=25v^2/v

v^2/v=v

350=25v

v=350/25

v=14 m/s

5 0
4 years ago
Q11) If you were standing at the top of a building and you dropped a rock.
Dafna1 [17]

Answer:

Part A

The distance travel by the rock is approximately 132.496 m

Part B

The speed when the rock hits the ground is approximately 50.96 m/s

Explanation:

Part A

The question is focused on the kinetics equation of a free falling object

The given parameter is the time it takes the rock to hit the ground, t = 5.2 s

For an object in free fall, we have;

h = 1/2·g·t²

Where;

h = The height from which the object is dropped

g = The acceleration due to gravity ≈ 9.8 m/s²

t = The time taken to travel the distance, h = 5.2 s

∴ h = 1/2 × 9.8 m/s² × (5.2 s)² ≈ 132.496 m

The distance travel by the rock, h ≈ 132.496 m

Part B

The speed, 'v', when the rock hits the ground, is given by the following kinematic equation,

v = g·t

∴ v = 9.8 m/s² × 5.2 s = 50.96 m/s

The speed when the rock hits the ground, v ≈ 50.96 m/s.

8 0
3 years ago
Other questions:
  • A large balloon is initially filled to a volume of 25.0 l at 353 k and a pressure of 2575 mm hg. what volume of gas will the bal
    13·1 answer
  • Two boats start together and race across a 48-km-wide lake and back. Boat A goes across at 48 km/h and returns at 48 km/h. Boat
    7·1 answer
  • The melting point of potassium thiocyanate determined by a student in the laboratory turned out to be 174.5 oC. The accepted val
    10·1 answer
  • Suppose you want to to double a copper wire's resistance. To what temperature, in degrees Celsius, must you raise it if it is or
    7·1 answer
  • What isFigure ground in psychology
    13·1 answer
  • Click to review the online content. Then answer the question(s) below, using complete sentences. Scroll down to view additional
    10·2 answers
  • A 1200 N force acts on an object, resulting in an acceleration of 8.0 m/s2. What is the mass of the object?
    10·1 answer
  • The rates of obesity have more than doubled for children between the ages of 6 and 11 since the middle of the twentieth century.
    15·1 answer
  • A wave has frequency of 50 Hz and a wavelength of 10 m. What is the speed of the wave? Group of answer choices
    10·1 answer
  • What is density of gold
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!