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andrew11 [14]
3 years ago
13

A total charge of 6.3×10−8 C is distributed uniformly throughout a 2.7-cm radius sphere. The

Physics
2 answers:
Likurg_2 [28]3 years ago
5 0

Answer:

The volume charge density of the sphere is 7.64\times 10^{-4}\ C/m^3.

Explanation:

It is given that,

Charge, q=6.3\times 10^{-8}\ C

Radius of the sphere, r = 2.7 cm = 0.027 m

Total charge contained divided by its volume is called volume charge density. Mathematically, it is given by :

\rho=\dfrac{Q}{V}

\rho=\dfrac{Q}{4/3\pi r^3}

\rho=\dfrac{6.3\times 10^{-8}}{4/3\pi (0.027)^3}

\rho=7.64\times 10^{-4}\ C/m^3

So, the volume charge density of the sphere is 7.64\times 10^{-4}\ C/m^3. Hence, this is the required solution.

stiks02 [169]3 years ago
4 0
The density is 3.7 x 10-7 C/ m3
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m = 14*26 = 364

Explanation:

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\frac{1}{v_{0}}-\frac{1}{u_{0}}=\frac{1}{f_{0}}

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