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3 years ago

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The acceleration due to gravity on the surface of Mars is about one-third the acceleration due to gravity on Earthâ€™s surface.

The weight of a space probe on the surface of Mars is about:a. nine times greater than its weight on Earthâ€™s surface.b. three times greater than its weight on Earthâ€™s surface.c. one-third its weight on Earthâ€™s surface.d. the same as its weight on Earthâ€™s surface.

1 answer:

aksik [14]3 years ago

6 0

Answer:

one-third of its weight on Earth's surface

Explanation:

Weight of an object is = W = m*g

Gravity on Earth = g₁ = 9.8 m/s

Gravity on Mars = g₂ = $\frac{1}{3}$ g₁

Weight of probe on earth = w₁ = m * g₁

Weight of probe on Mars = w₂ = m * g₂ -------- ( 1 )

As g₂ = g₁/3 --------- ( 2 )

Put equation (2) in equation (1)

so

Weight of probe on Mars = w₂ = m * g₁ /3

Weight of probe on Mars = $\frac{1}{3}$ m * g₁ = $\frac{1}{3}$ w₁

⇒Weight of probe on Mars = $\frac{1}{3}$ Weight of probe on earth

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At time t=0 a grinding wheel has an angular velocity of 28.0 rad/s . It has a constant angular acceleration of 35.0 rad/s2 until

notsponge [240]

Answer:

a). $x_{t}=583.3rad$

b). $t_{total}=10.52s$

c). $a=12.62 \frac{rad}{s^2}$

Explanation:

The angular acceleration is constant so we can use the formulas of uniform motion with the model of angular acceleration

a).

$x_{r}=x_{i}+v_{i}+\frac{1}{2}a_{a}*t^2$

$x_{r}=0+28.0\frac{rad}{s}*2.20s+\frac{1}{2}*35.0\frac{rad}{s^2}*2.20s$

$x_{r}=146.3rad$

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$x_{t}=146.3rad+437rad=583.3rad$

b).

$w_{f}=w_{o}+a*t$

$w_{f}=28.0rad/s+35rad/s^2*2.2s=105rad/s$ = $w_{o}$

$x_{t}-x_{r}=\frac{1}{2}*(w_{o}-w_{f})*t$

$583.3-146.3=\frac{1}{2}*(105-0)*t$

$t=\frac{437rad}{105\frac{rad}{s}}=8.32s$

$t_{total}=8.32+2.2=10.52s$

c).

$w_{f}=w_{o}+a*t$

$0=105 rad/s+a*8.32s$

$a=\frac{105 rad/s}{8.32s}$

$a=12.62 \frac{rad}{s^2}$

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Period = 6 seconds and $frequency = 0.167Hz$ .

<u>Explanation:</u>

We have , the motion of a swing that requires 6 seconds to complete one cycle. Period is the amount of time needed to complete one oscillation . And in question it's given that 6 seconds is needed to complete one cycle. Hence ,Period of the motion of a swing is 6 seconds . Frequency is the number of vibrations produced per second and is calculated with the formula of $\frac{1}{t}$ . SI unit of frequency is Hertz or Hz. We know that time period is 6 seconds so frequency = $\frac{1}{t}$

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