At the instant the second bulb is connected ...
... the brightness of the <u>first bulb</u> doesn't change
... the brightness of the <u>second bulb</u> changes from dark (no brightness) to equal to the first bulb
The dragster's velocity <em>v</em> at<em> </em>time <em>t</em> with constant acceleration <em>a</em> is
since it starts at rest.
After 2.1 s, it will attain a velocity of
or 92.4 m/s.
Doubling the time would double the final velocity,
so the velocity would be twice the previous one, 184.8 m/s.
The dragster undergoes a displacement <em>x</em> after time <em>t</em> with acceleration <em>a</em> of
if we take the starting line to be the origin.
After 2.1 s, it will have moved
or 88 m.
Doubling the time has the effect of quadrupling the displacement, since
so after 4.2 s it will have moved 352 m.
Gravity will have a greater effect on an object with a heavier mass
Answer:
The buoyant force on the wood = 7.652 N
Explanation:
According to the principle of flotation, a body floats when the upthrust exerted upon it by the fluid n which it floats equals the weight of the body.
W = U ............... Equation.
Where W = weight of the wood, U = Upthrust or buoyant force.
Recall That,
Density = mass/volume
Mass = Density×volume
m = D×V........................ Equation 2
Where m = mass of the wood, V = Volume of the wood, D = Density of the wood.
But
Volume of a cube = a³
V = a³ where a = length of the cube.
V = 10³ = 1000 cm³.
Given: V = 1000 cm³ D = 0.780 g/cm³
Substituting these values into equation 2,
m = 1000(0.780)
m = 780 g
m = 0.78 kg.
But W = mg
Where m = 0.78 kg, g = 9.81 m/s²
W = 0.78(9.81)
W = 7.652 N.
Since W = U = 7.652 N.
U = 7.652 N
Therefore the buoyant force on the wood =7.652 N
