Question

I need geometry help pleas will give brainliest

Answer 1

to the risk of sounding redundant.

$\bf \textit{area of a segment of a circle}\\\\ A=\cfrac{r^2}{2}\left(\cfrac{\pi \theta }{180}-sin(\theta ) \right)~~ \begin{cases} r=&radius\\ \theta =&angle~in\\ °rees\\ \cline{1-2} r=&6\\ \theta =&60 \end{cases}\implies A=\cfrac{6^2}{2}\left(\cfrac{\pi 60}{180}-sin(60^o ) \right) \\\\\\ A=18\left( \cfrac{\pi }{3}-\cfrac{\sqrt{3}}{2} \right)\implies \boxed{A=6\pi -9\sqrt{3}}\implies \implies A\approx 3.26$

Answer 2

Answer:

6π - 9√3 unit^2

Step-by-step explanation:

Area of sector

= 1/6(π (6)^2

= 6π

Area of triangle = √3/4 (6)^2 = 9√3

Area of the shaded segment = Area of sector - Area of triangle

= 6π - 9√3 unit^2