Answer:
29.4 cm
Step-by-step explanation:
The length of the space diagonal can be found to be the root of the squares of the three orthogonal edge lengths. For a cube, those edge lengths are all the same, so the diagonal length is ...
d = √(17^2 + 17^2 +17^2) = 17√3 ≈ 29.4 . . . . cm
_____
Consider a rectangular prism with edge lengths a, b, c. Then the face diagonal of the face perpendicular to edge "a" has length ...
(face diagonal)^2 = (b^2 +c^2)
and the space diagonal has length ...
(space diagonal)^2 = a^2 + (face diagonal)^2 = a^2 +b^2 +c^2
So, the length of the space diagonal is ...
space diagonal = √(a^2 +b^2 +c^2)
when the prism is a cube, these are all the same (a=b=c). This is the formula we used above.
Answer:
$700
Step-by-step explanation:
25 the least amount of money earned by each student multiplied by 28 the number of students.
Mercury has the greater density than that of Venus .
Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
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