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-BARSIC- [3]
3 years ago
15

What is 3x+8=14 in algebra tiles

Mathematics
2 answers:
kipiarov [429]3 years ago
8 0

Answer: Not really sure what you mean by algebra tiles but I do know that x=2.

AfilCa [17]3 years ago
6 0

Answer:

2

Step-by-step explanation:

3x+8=14

   -8   -8

    3x  6

     x=2

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The edge length of a cube is 17 cm. Identify the length of its diagonal. Round to the nearest tenth, if necessary. HELP PLEASE!!
lara31 [8.8K]

Answer:

29.4 cm

Step-by-step explanation:

The length of the space diagonal can be found to be the root of the squares of the three orthogonal edge lengths. For a cube, those edge lengths are all the same, so the diagonal length is ...

d = √(17^2 + 17^2 +17^2) = 17√3 ≈ 29.4 . . . . cm

_____

Consider a rectangular prism with edge lengths a, b, c. Then the face diagonal of the face perpendicular to edge "a" has length ...

(face diagonal)^2 = (b^2 +c^2)

and the space diagonal has length ...

(space diagonal)^2 = a^2 + (face diagonal)^2 = a^2 +b^2 +c^2

So, the length of the space diagonal is ...

space diagonal = √(a^2 +b^2 +c^2)

when the prism is a cube, these are all the same (a=b=c). This is the formula we used above.

3 0
3 years ago
each of the 28 students in romi's class raised at least $25 during the jump-a-thon. what is the least amount of money the class
AlladinOne [14]

Answer:

$700

Step-by-step explanation:

25 the least amount of money earned by each student multiplied by 28 the number of students.

4 0
3 years ago
The volume of a pyramid that fits exactly inside a cube is 10 cubic feet. What is the volume of the cube?
Tatiana [17]

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the cubic feet will be 1000

6 0
3 years ago
HELPPPP please !!!!!,!!?
lions [1.4K]

Mercury has the greater density than that of Venus .

4 0
3 years ago
Read 2 more answers
Please help fast.
podryga [215]

\huge{\underline{\boxed{\tt{Answer:}}}}

Let AB be a chord of the given circle with centre and radius 13 cm.

Then, OA = 13 cm and ab = 10 cm

From O, draw OL⊥ AB

We know that the perpendicular from the centre of a circle to a chord bisects the chord.

∴ AL = ½AB = (½ × 10)cm = 5 cm

From the right △OLA, we have

OA² = OL² + AL²

==> OL² = OA² – AL²

==> [(13)² – (5)²] cm² = 144cm²

==> OL = √144cm = 12 cm

Hence, the distance of the chord from the centre is 12 cm.

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8 0
3 years ago
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