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FromTheMoon [43]
2 years ago
13

Hey, can anyone help me out ASAP!! Will give Brainliest!! Fairly easy geometry, multiple choice!!

Mathematics
2 answers:
ser-zykov [4K]2 years ago
8 0

Answer:

The 3rd option, so C

Step-by-step explanation:

umka2103 [35]2 years ago
5 0

Answer:

C.

Step-by-step explanation:

A square cannot be a rhombus because it has a right angle.

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Please need help fast. Look at the pictures.
Leya [2.2K]
It will definitely be a positive
5 0
3 years ago
What is the solution to the equation 3 square root x+4+3 square root 2x+8=0? x = –12 x = –4 x = 4 x = 12
Gre4nikov [31]

Answer:

x=-4

Step-by-step explanation:

3 0
3 years ago
Suppose that 37% of college students own cats. If you were to ask random college students if they own a cat what would the proba
Likurg_2 [28]

Using the binomial distribution, the probabilities are given as follows:

a) 0.37 = 37%.

b) 0.5065 = 50.65%.

c) 0.3260 = 32.60%.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

For this problem, the fixed parameter is:

p = 0.37.

Item a:

The probability is P(X = 1) when n = 1, hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{1,1}.(0.37)^{1}.(0.63)^{0} = 0.37

Item b:

The probability is P(X = 3) when n = 3, hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{3,3}.(0.37)^{3}.(0.63)^{0} = 0.5065

Item c:

The probability is P(X = 2) when n = 4, hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{4,2}.(0.37)^{2}.(0.63)^{2} = 0.3260

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

4 0
2 years ago
I need help with this
PIT_PIT [208]
2x+8y
2x+8times2
2x+16
18x
Your final answer is 18x!
7 0
3 years ago
Read 2 more answers
A particular paper included the accompanying data on the tar level of cigarettes smoked for a sample of male smokers who subsequ
Dafna1 [17]

Answer:

Check the explanation

Step-by-step explanation:

H_0:proportion of male smoker lung deaths is same for the four given tar level categories.

H_1:proportion of male smoker lung deaths is not the same for the four given tar level categories.

Expected frequency=1177/4=294.25

Tar level     Observed Freq.(O)        Expected Freq.(E)         (O-E)^2/E

0-7                         107                                   294.25                120.435

8-14                        375                                  294.25                5.643

15-21                       553                                 294.25                 227.533

>=22                       183                                  294.25                 42.061

Total=                    1177                                  1177                      395.673

Total chi square score=395.673

df=4-1=3

p-value=CHIDIST(395.673,3)<0.001

p-value<0.001,Reject null hypothesis.

There is sufficient evidence that the proportion of male smoker lung deaths is not the same for the four given tar level categories.

5 0
3 years ago
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