Question

If there are 25,682 people living in Jarvieville in 2015, and the population increases 20% each year...

Answer 1

Answer:

$f(x)=25,682(1.2)^{t}$

44378.496=44,379

Step-by-step explanation:

We can write the equation using a growth equation $f(x)=P(1+r)^{t}$ where:

• P is the starting value
• r is the percent or rate as a decimal
• t is years

We will substitute into the formula P=25,682, r=0.2 and t =3 for 3 years since 2018 is 3 years after 2015.

$f(x)=25,682(1+0.2)^{3}$

$f(x)=25,682(1.2)^{3}$

$f(x)=44378.496$