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kaheart [24]
3 years ago
14

Add the following polynomails -3x^2-2xy+y^2,-4x^2-xy+6y^2, x^2+6xy-y^2

Mathematics
1 answer:
Tomtit [17]3 years ago
8 0

Answer:

When we add the given polynomials the result is

(-3x^2-2xy+y^2)+(-4x^2-xy+6y^2)+(x^2+6xy-y^2)=3(2(y^2-x^2)+xy)

Step-by-step explanation:

Given polynomials are

-3x^2-2xy+y^2 ,-4x^2-xy+6y^2 , x^2+6xy-y^2

Now addding the polynomials we get

(-3x^2-2xy+y^2)+(-4x^2-xy+6y^2)+(x^2+6xy-y^2)=-3x^2-2xy+y^2+-4x^2-xy+6y^2+x^2+6xy-y^2

=-6x^2+3xy+6y^2  (adding the like terms on RHS)

=3(-2x^2+xy+2y^2)  (taking 3 outside on RHS)

=3(2(-x^2+y^2)+xy)

Rewritting the above equation we get,

=3(2(y^2-x^2)+xy)

Therefore (-3x^2-2xy+y^2)+(-4x^2-xy+6y^2)+(x^2+6xy-y^2)=3(2(y^2-x^2)+xy)

When we add the given polynomials the result is

(-3x^2-2xy+y^2)+(-4x^2-xy+6y^2)+(x^2+6xy-y^2)=3(2(y^2-x^2)+xy)

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Answer:

A≈1075.21

d Diameter

37

d

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5 0
3 years ago
Select all answers that have a value of 22?? Help..
Tom [10]

Let's plug in the variables one by one.

6g - 2h

plug in 5 for g and 4 for h

6(5) - 2(4)

multiply

30 - 8

subtract

→ 22

20g

plug in 2 for g

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multiply

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plug in 10 for g

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multiply

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4g + 5h

plug in 1 for g and 4 for h

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multiply

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24

Therefore, the answers that have a value of 22 are 6g - 2h and 2(g + 1)

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4 years ago
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Find the prime factorization of 2001
marusya05 [52]
Rime factorization of 2001: 

By prime factorization of 2001 we follow 5 simple steps: 
1. We write number 2001 above a 2-column table 
2. We divide 2001 by the smallest possible prime factor 
3. We write down on the left side of the table the prime factor and next number to factorize on the ride side
4. We continue to factor in this fashion (we deal with odd numbers by trying small prime factors)
5. We continue until we reach 1 on the ride side of the table

<span>2001<span>prime factorsnumber to factorize</span><span>3667</span><span>2329</span><span>291</span></span>

<span>Prime factorization of 2001 = 1×3×23×29= </span><span>1 × 3 × 23 × 29</span>
4 0
3 years ago
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