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Verizon [17]
3 years ago
8

What is the square root of 16x36? 4x6 4x18 8x6 8x18

Mathematics
2 answers:
elixir [45]3 years ago
6 0

Answer:

the correct answer to this is B

Step-by-step explanation:


Ksenya-84 [330]3 years ago
4 0
To obtain the square root of 16x^36, the coefficient portion (16) will not present any problems since 16 is a perfect square. However, for a variable with an exponent, the exponent is to be multiplied by 1/2 since the square root symbol is equal to raising the term inside to the power of 1/2. This is shown below:

sqrt (16 x^36) = 4 * x^36(1/2) = 4 * x^18

Therefore, the correct answer is 4x^18. 
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What is the slope of a line perpendicular to the line whose equation is
mezya [45]

Answer:

The slope of the other line is -4/5

Step-by-step explanation:

In this question, we are asked to calculate the slope of a line which is perpendicular to the line ;

10x - 8y = -80

The first thing to do here is to write the equation in the standard form for a linear equation.

The standard form is y = mx + c where m refers to the slope and c refers to the y-intercept

Rewriting the equation we have;

8y-80 = 10x

8y = 10x + 80

Now divide the through by 8

We have;

y = 10x/8 + 10

Thus, comparing with y = mx + c , our m here is 10/8

Now for the two lines to be perpendicular, the product of their slope would be equals to -1

Let’s say the slopes are m1 and m2

mathematically m1m2 = -1

since m1 = 10/8

10m2/8 = -1

m2 = -8/10

m2 = -4/5

7 0
3 years ago
What is 23/52 simplified
Nookie1986 [14]
It is simplified as much as it can go. 
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3 years ago
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Which of the following is true about a function that is constant? (4 points)
Lemur [1.5K]
It moves in a horizontal line.  Its 'y value' does not change.
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3 years ago
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L 5.2.2 Quiz: Calculating Credit Card Interest
Ne4ueva [31]

Answer:

Below.

Step-by-step explanation:

The correct answer is D. Average daily balance method.

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3 years ago
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Please please help me out!!!!!
NeX [460]

Answer:

see explanation

Step-by-step explanation:

By the rational root theorem, any rational roots of f(x) are expressible in the form

\frac{p}{q} for integers p and q

with p a divisor of the constant term 6 and q a divisor of the leading coefficient 1.

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Since the lead coefficient is 1 dividing by that number doesn't change a thing.

Thus the possible rational roots are

\frac{p}{q} = - 6, - 3, - 2, -1, 1, 2, 3, 6

6 0
3 years ago
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