Student A starts with $100 in the bank and makes $5 a day. Student B starts with $50 and makes $7 a day. Assuming the students save their money, when will they have the same amount of money ?
Answer:
x = -1
Step-by-step explanation:
1. Simplifying
6x + 4 = 4x + 2
2. Reorder the terms
4 + 6x = 4x + 2 to 4 + 6x = 2 + 4x
3. Solving
4 + 6x = 2 + 4x
4. Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right. Then add '-4x' to each side of the equation.
4 + 6x + -4x = 2 + 4x + -4x
5. Combine like terms: 6x + -4x = 2x
4 + 2x = 2 + 4x + -4x
6. Combine like terms: 4x + -4x = 0
4 + 2x = 2 + 0
4 + 2x = 2
7. Add '-4' to each side of the equation.
4 + -4 + 2x = 2 + -4
8. Combine like terms: 4 + -4 = 0
0 + 2x = 2 + -4
2x = 2 + -4
9. Combine like terms: 2 + -4 = -2
2x = -2
10. Divide each side by '2'.
x = -1
11. Simplifying
x = -1
Answer:
Initial Value / Starting Point
Step-by-step explanation:
Slope-intercept form of a linear equation is y=mx+b where m is the slope and b is the y-intercept, or the initial value.
$750.00 rent
x 12 months
_____________________
$ 9000.00 income
hope this helps,
~ Harley Quinn~
Answer:
(a)18
(b)1089
(c)Sunday
Step-by-step explanation:
The problem presented is an arithmetic sequence where:
- First Sunday, a=1
- Common Difference (Every subsequent Sunday), d=7
We want to determine the number of Sundays in the 120 days before Christmas.
(a)In an arithmetic sequence:
Since the result is a whole number, there are 18 Sundays in which Aldsworth advertises.
Therefore, Aldsworth advertised 18 times.
(b)Next, we want to determine the sum of the first 18 terms of the sequence
1,8,15,...
The sum of the numbers of days published in all the advertisements is 1089.
(c)SInce the 120th day is the 18th Sunday, Christmas is on Sunday.
