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3 years ago

What is a ratio equivalent to 3:2? (not 6:1)

Mathematics

1 answer:

Akimi4 [234]3 years ago

4 0

Answer:

9:6, 12:8, and 15:10 are all ratios equivalent to 3:2

Step-by-step explanation:

To find an equal ratio, you can either multiply or divide each term in the ratio by the same number (but not zero).

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Two angels of a triangle measure 65 and 75. Which is not the measure of an exterior angle of the triangle

Andre45 [30]

An exterior angle is the sum of the two other interior angles

the three interior angles are 55 and 65 and 180-(55+65)=60 

so 60 + 55 = 115 
60 + 65 = 125 
65 + 55 = 120

brainlest answer.

3 0

3 years ago

A road perpendicular to a highway leads to a farmhouse located d miles away. An automobile traveling on this highway passes thro

pshichka [43]

Answer:

$\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}$

Step-by-step explanation:

A road is perpendicular to a highway leading to a farmhouse d miles away.

An automobile passes through the point of intersection with a constant speed $\frac{dx}{dt}$ = r mph

Let x be the distance of automobile from the point of intersection and distance between the automobile and farmhouse is 'h' miles.

Then by Pythagoras theorem,

h² = d² + x²

By taking derivative on both the sides of the equation,

$(2h)\frac{dh}{dt}=(2x)\frac{dx}{dt}$

$(h)\frac{dh}{dt}=(x)\frac{dx}{dt}$

$(h)\frac{dh}{dt}=rx$

$\frac{dh}{dt}=\frac{rx}{h}$

When automobile is 30 miles past the intersection,

For x = 30

$\frac{dh}{dt}=\frac{30r}{h}$

Since $h=\sqrt{d^{2}+(30)^{2}}$

Therefore,

$\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+(30)^{2}}}$

$\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}$

3 0

3 years ago

Prove whether the following are identities 2tanh 1/2x / 1−tanh^2 1/2 x = sinh x

Tanzania [10]

Recall that

$\cosh^2(x) - \sinh^2(x) = 1$

Dividing both sides by cosh²(x) gives

$1 - \tanh^2(x) = \mathrm{sech}^2(x)$

Also, recall the identity

$\sinh(2x) = 2\sinh(x)\cosh(x)$

Then

$\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \dfrac{2\tanh\left(\frac x2\right)}{\mathrm{sech}^2\left(\frac x2\right)} \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\tanh\left(\dfrac x2\right)\cosh^2\left(\dfrac x2\right) \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\sinh\left(\dfrac x2\right)\cosh\left(\dfrac x2\right) \\\\\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \sinh(x)$

4 0

3 years ago

How do I solve This

Masja [62]

Answer:

v^21 v^3 is the answer by Alena

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Match the equation with its corresponding solution for x. 4x + 7 = 35

lyudmila [28]

Are you wanting to solve for x? If so:
4x + 7 = 35
We want to isolate the variable, so subtract 7 from both sides. You will get:
4x = 28
Now, divide each side by 4 to get X by alone. This will give you:
x = 7
I hope this helped.

8 0

3 years ago