All categories

2 years ago

I will mark u brainlist if u answer find the mistake... 4x + x = 30 –6 4x = 24 4 24 4 4 x x = 6

Mathematics

1 answer:

Jlenok [28]2 years ago

4 0

Answer:

The mistake is that 4x+x = 5x not 4x

Step-by-step explanation:

4x + x = 30 –6

Combine like terms

5x = 24

Divide each side by 5

5x/5 = 24/5

x = 24/5

The mistake is that 4x+x = 5x not 4x

You might be interested in

PLEASE HELP I WILL MARK THE BRAINLIEST

-BARSIC- [3]

Given: lines l and m are parallel, and line t is a transversal.

angle pair result/justification

1 and 2 are equal (vertical angles)

6 and 8 are equal (corresponding angles)

1 and 4 are equal (alternate exterior angles)

4 and 8 are supplementary angles (i.e. add up to 180 degrees, a straight angle)

Note:

alternate angles are on opposite sides of the transversal, and each attached to a different (parallel) line.

If they are both enclosed by the parallel lines, they are alternate interior angles (examples: angles 2 and 3, 6 and 7)

If they are both outside of the two parallel lines, they are alternate exterior angles (examples: angles 1 and 4, 5 and 8)

8 0

2 years ago

Read 2 more answers

5.Karen is thinking of a number. If she multiplies her number by −3 and then adds 6, she has −4 times the original number. What

alekssr [168]

-3x+6 = -4x

6 = -x

x = -6

check:

-6*-3 = 18 +6 =24

-6*-4 = 24

number = -6

5 0

2 years ago

What statement is true about these two triangles?

timofeeve [1]

Answer:

Step-by-step explanation:

5 0

2 years ago

29 — 6x=5(1 – 6x) Please show me the steps

Lady bird [3.3K]

Answer:

x= -1

Step-by-step explanation:

START 29 - 6x = 5(1 - 6x)

1. Distribute

29 - 6x = 5 - 30x

2. Isolate the variable

~ 2a. Add 30x to both sides

29 - 6x + 30x = 5 - 30x + 30x

~ 2b. Subtract 29 from both sides

29 - 29 - 6x + 30x = 5 - 29 - 30x + 30x

3. Simplify

24x = -24

4. Solve

x = -1

END

5 0

2 years ago

Does anyone know how to graph trigonometric functions for algebra 2?

anastassius [24]

Solution:

Give the following below

$\begin{gathered} amplitude=3 \\ period=\frac{\pi}{2} \\ midline,\text{ }y=-1 \\ Passing\text{ through the point }(0,2) \end{gathered}$

To find the cosine function, we will apply the general formula for cosine function below

$\begin{gathered} f(x)=a\cos(bx-c)+d \\ Where \\ a\text{ is the amplitude} \\ b\text{ represents the speed of the cycle} \\ d\text{ is the vertical shift} \\ \frac{c}{b}\text{ is the phase shift \lparen horizontal shift\rparen} \\ Period=\frac{2\pi}{b} \end{gathered}$

To find the value of b

$\begin{gathered} Period=\frac{\pi}{2} \\ \frac{2\pi}{b}=\frac{\pi}{2} \\ Crossmultiply \\ b\times\pi=2\times2\pi \\ b=\frac{4\pi}{\pi} \\ b=4 \end{gathered}$ $\begin{gathered} a=3 \\ b=4 \\ d=-1 \\ c=0 \end{gathered}$

Substitute the values of the variables into the general formula for cosine function

$\begin{gathered} f(x)=a\cos(bx-c)+d \\ f(x)=3\cos(4x-0)-1 \\ f(x)=3\cos4x-1 \end{gathered}$

Applying a graphing tool,

The graph of one cycle of the function is shown below

4 0

9 months ago