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s344n2d4d5 [400]
3 years ago
15

On January 22, 1943, the temperature in Spearfish, South Dakota, rose from -4.0∘F∘F to 45.0∘F∘F in just 2 minutes. What was the

temperature change in Celsius degrees?
Physics
1 answer:
Margaret [11]3 years ago
8 0

Answer:

The change in temperature, \Delta T=9.45^{\circ} C

Explanation:

Given that,

The temperature in Spearfish, South Dakota, rose from -4^{\circ} F\ to\ 45^{\circ} F in just 2 minutes. We need to find the temperature change in Celsius degrees. Change in temperature is given by final temperature minus initial temperature such that,

\Delta T=T_f-T_i\\\\\Delta T=45-(-4)\\\\\Delta T=49^{\circ}F

The relation between degrees Celsius and degrees Fahrenheit is given by :

F=1.8C+32

Here, F = 49 degrees

49=1.8C+32\\\\\Delta T=9.45^{\circ} C

So, the change in temperature is 9.45 degree Celsius. Hence, this is the required solution.

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Len [333]

Answer:

v=1.295

Explanation:

What we are given:

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<em>Integrating</em>

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Use Simpson's rule for the right site.

\int\limits^a_b {x} \, dx

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<em>b=a</em>

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f(x)=b-a/6*(f(a)+4f(a+b/2)+f(b)

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3 years ago
The specific heat of water is 4.18 J/gºC. How many Joules of
densk [106]

Answer:

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Explanation:

In order to calculate the amount of thermal energy needed we must use the following equation.

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