Answer:
So then we will have at least 75% of the data within two deviations from the mean 
.
So then the interval would be (97.14, 99.5)
Explanation:
Previous concepts
Chebyshev’s rule is appropriate for any distribution. "Chebyshev’s inequality applies to all distributions, regardless of shape". And is useful since provides a "minimum percentage of the observations that lies within k standard deviations of the mean. "
If k = 2, at least 3/4 of the measurements lie within 2 standard deviations to within the mean.
And the general formula is (1-1/k^2) represent the fraction of the data within the mean .
Solution to the problem
For this case we want to find the percentage of data that would be at least within two deviations from the mean so for this case the value of k =2 and if we replace we got:
So then we will have at least 75% of the data within two deviations from the mean .
For the other part we have the mean and deviation provided 
the interval would be:
So then the interval would be (97.14, 99.5)
Answer:
Yellow.
Explanation:
An object that reflects all the incidents colors of light will surely reflect off the color yellow, and when the reflected ray hits our eyes, we will perceive the object as yellow. The object that reflects off all colors appears to us as white. So if you want to make sure, then just shine yellow light on a white fabric and see what happens!
What you will observe of course is a yellow fabric. Similarly, if you shine red light onto the fabric, it will appear red, and so on for all colors.
Answer:
a) W = - 1.752 10⁻¹⁸ J, b) U = + 1.752 10⁻¹⁸ J
Explanation:
a) work is defined by
W = F . x
the bold letters indicate vectors, in this case the force is electric
F = q E
we substitute
F = q E x
the charge of the electron is
q = - e
F = - e E x
let's calculate
W = - 1.6 10⁻¹⁹ 365 3 10⁻²
W = - 1.752 10⁻¹⁸ J
b) the change in potential energy is
U = q ΔV
the potential difference is
ΔV = - E. Δs
we substitute
U = - q E Δs
the charge of the electron is
q = - e
U = e E Δs
we calculate
U = 1.6 10⁻¹⁹ 365 3 10⁻²
U = + 1.752 10⁻¹⁸ J
