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rjkz [21]
3 years ago
7

How does natural selection produce change in a population of mice?

Physics
1 answer:
sergey [27]3 years ago
5 0

Answer:

The population of the mice will decrease to the faster, stronger, and smarter mice because the weaker will die because of natural selection.

Explanation:

You might be interested in
What distance will be traveled if you are going 120km/hr for 30 min?
nikklg [1K]

Answer:

60 km

Explanation:

For an object (or a person, such as in this case) moving at constant speed, the speed is equal to the ratio between the distance travelled and the time taken:

v=\frac{d}{t}

where

v is the speed

d is the distance

t is the time taken

In this case, we have:

v = 120 km/h is the speed

t = 30 min = 0.5 h is the time taken

Therefore, we can rearrange the equation to find the total distance travelled:

d=vt=(120)(0.5)=60 km

3 0
3 years ago
For a spacecraft or a molecule to leave the moon, it must reach the escape velocity (speed) of the moon, which is 2.37 km/s. The
guapka [62]

Answer:

Vrms = 291 m/s

Explanation:

The root mean square velocity or vrms is the square root of the average square velocity and is. vrms=√3RTM. Where M is equal to the molar mass of the molecule in kg/mol.

Temperature = 365 K

Root mean square velocity = ?

molar mass of oxygen = 16 g/mol.

But xygen gas (O2) is comprised of two oxygen atoms bonded together. Therefore:

   molar mass of O2 = 2 x 16

   molar mass of O2 = 32 g/mol

   Convert this to kg/mol:

   molar mass of O2 = 32 g/mol x 1 kg/1000 g

   molar mass of O2 = 3.2 x 10-2 kg/mol

Molar mass of Oxygen = 3.2 x 10-2 kg/mol

Vrms = √[3(8.3145 (kg·m2/sec2)/K·mol)(365 K)/3.2 x 10-2 kg/mol]

Vrms = 291 m/s

8 0
4 years ago
Read 2 more answers
The radius of Earth is about 6450 km. A 7070 N spacecraft travels away from Earth. What is the weight of the spacecraft at a hei
Triss [41]

Answer:

(a) 1767.43 N

(b) 182.45 N

Explanation:

Radius of earth, R = 6450 km

Weight of person, W = 7070 N

mass of person, m = W / g = 7070 / 9.8 = 721.4 kg

(a) h = 6450 km

The value of acceleration due to gravity on height is given by

g' = g\left ( \frac{R}{R+h} \right )^2

g' = g\left ( \frac{6450}{6450+6450} \right )^2

g' = g / 4 = 9.8 / 4 = 2.45 m/s^2

The weight of the person at such height is

W' = m x g' = 721.4 x 2.45

W' = 1767.43 N

(b) h = 33700 km

The value of acceleration due to gravity on height is given by

g' = g\left ( \frac{R}{R+h} \right )^2

g' = g\left ( \frac{6450}{6450+33700} \right )^2

g' = g x 0.0258 = 9.8 x 0.0258 = 0.253 m/s^2

The weight of the person at such height is

W' = m x g'

W' = 721.4 x 0.253

W' = 182.45 N

3 0
3 years ago
Find the slope of the line that passes through the points (-1, 3) and (2, -5)-
spayn [35]

Answer:

m=−8/3

Explanation:

6 0
3 years ago
Read 2 more answers
Rosa uses the formula (vi cos)t to do a calculation. Which value is Rosa most likely trying to find? the vertical acceleration o
blagie [28]
The horizontal displacement of a projectile launched at an angle
4 0
3 years ago
Read 2 more answers
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