The acceleration formula goes like this: a= (vf-vi)/t so it would be (13-4)/3 Thus the answer is 3m/s^2
Answer:
0.073 N-m
Explanation:
i = 12 A, l = 0.8 m, B = 0.12 T
The circumference of the loop is 0.8 m.
Let r be the radius of the loop.
2 x 3.14 x r = 0.8
r = 0.127 m
Maximum Torque = i x A x B
Maximum Torque = 12 x 3.14 x 0.127 x 0.127 x 0.12 = 0.073 N-m
I believe it’s 8.3 to be precise
Resistance of a wire is directly proportional to its length and inversely proportional to the square of its radius.
Thus, if the length is doubled, and the radius is halved:
R₂ = 2R₁/(1/2)²
R₂ = 8R₁
Therefore the resistance increases eight times.
