Question

The specific heat of water is 4.18 J/gºC. How many Joules of

Answer 1

Answer:

Q = 59565 [J]

Explanation:

In order to calculate the amount of thermal energy needed we must use the following equation.

$Q=m*C_{p}*(T_{i}-T_{f})$

where:

m = mass = 150 [g]

Cp = 4.18 [J/g*°C]

Tfinal = 5 [°C]

Tinitial = 100 [°C]

Now replacing:

$Q=150*4.18*(100-5)\\Q=59565[J]$