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3 years ago

7

Hey can u guys help me out please

1 answer:

Vinil7 [7]3 years ago

5 0

Yes they are congruent
Congruent means (In identical form)

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Select Yes or No to indicate whether each of the ordered pairs is most likely a solution to the equation represented by the grap

maria [59]

Yes, yes, no I believe

7 0

3 years ago

In the following monomial, what is the 5 called?

CaHeK987 [17]

Answer:

<em><u>5 is called coefficient</u></em>

<em><u> m is called variable </u></em>

<em><u>3 is called degree....</u></em>

6 0

3 years ago

Read 2 more answers

What is the value of i 97 – i?<br> –i<br> 0<br> –2i<br> i Superscript 96

Valentin [98]

<em>The question is not clearly readable, but I'm assuming the expression which makes more sense, so you can have a clue</em>

Answer:

$i^{97}-i=0$

Step-by-step explanation:

<u>Powers of The Imaginary Unit</u>

The imaginary unit i is defined as

$i=\sqrt{-1}$

The first powers of i are

$i^0=1$

$i^1=i$

$i^2=(\sqrt{-1})^2=-1$

$i^3=i.i^2=-i$

$i^4=i^2.i^2=1$

And so on the cycle repeats every four numbers. To find the value of $i^{96}$ we can find the remainder of 96/4=0. So $i^{96}=i^0=1$

The given expression is

$i^{97}-i$

Factoring

$i(i^{96}-1)$

Since $i^{96}=1$

$=i(1-1)=0$

The required value is 0

6 0

3 years ago

Read 2 more answers

Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

a)

when $x=-2, y=1$

Here $-2$ that is $x$ satisfied. Then

$(-2)^{2}$

$4$ this is wrong. since $4>1$

That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

b)

Assume $Q(x,y)=Q(-5,2)$ .

That is $x=-5, y=2$

Here $-5$ that is $x$ this condition is satisfied.

Then

$(-5)^{2}$

$25$ this is not true. since $25>4$ .

This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

c)

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

$9$ This also satisfies the condition $x^{2}$ .

Hence $Q(3,8)$ exists and it is true.

d)

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

$81$ satisfies the condition $x^{2}$ .

Thus, $Q(9,10)$ point exists and it is true. This satisfies the same values as in part (c)

6 0

3 years ago

HELP!!! SOLVE USING SUBSTITUTION OR ELIMINATION.

Bezzdna [24]

Search it up on the internet <3

8 0

3 years ago