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Ksivusya [100]
3 years ago
15

Which situation is best met through long-term saving?

Mathematics
1 answer:
Masja [62]3 years ago
7 0
An unexpected medical bill I’m pretty sure
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The mean age of Mr Jasmi,Miss Haslinda and their three children is 38 years. The mean age of their three children is 18 years. C
DedPeter [7]
Answer: 68

Explanation:

Let x be the age of Mr Jasmi
y be the age of Miss Haslinda
a + b + c be the age of the 3 children

We can write:
(x + y + a + b + c)/5 = 38

But:
(a + b + c)/3 = 18
a + b + c = 18(3)
a + b + c = 54

Substitute this value to our first equation

(x + y + 54)/5 = 38
x + y + 54 = 38(5)
x + y + 54 = 190
x + y = 190 - 54
x + y = 136

Thus:
Mean age of (mr jasmi and miss Linda) = (x+y)/2

But x + y = 136

=> mean age = 136/2 = 68
4 0
2 years ago
If x = 7 and f = 4 and g = 9 and l = 24 and p = 12 and e = 9847493 then what is x ÷ fg X i ÷ p
REY [17]
0.38^• or 7/18. If the x after the g and before the i is a multiplication (btw the ^• is a repeater
3 0
2 years ago
Solve for x in the equation x2+2x+1=17
Sphinxa [80]
If you meant 2x + 2x + 1 = 17: x = 4
Solve for x by simplifying both sides of the equation, then isolating the variable.<span> 
</span>
If you meant <span>x2 + 2x + 1 = 17:</span> <span>x ≈ 3.1231056,−5.1231056x</span>
Solve the equation for x by finding a, b, and c of the quadratic then applying the quadratic formula. <span><span>x = −1 ± <span>√17</span></span>x</span>
7 0
3 years ago
Read 2 more answers
If 3 pounds of chocolate cost $25.50 how many pounds can you buy for $42.50
MrMuchimi
To solve this, write a proportion of Pounds to Cost:
Pounds:     3         x
     Cost: 25.50   42.50

Cross multiply 3 and 42.50, this gives you 127.5
Then, divide by 25.5
This gives you 5.
You can buy 5 pounds with $42.50
8 0
2 years ago
Read 2 more answers
Anika is 7 years older than Kit. If Kit is k years old, how old is Anika?
zaharov [31]

Answer:

k+7

Step-by-step explanation:

because k is the age of kit so Anika is 7 years older, so u have to add

sorry if I'm wrong

7 0
3 years ago
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