<span>Consider a angle â BAC and the point D on its defector
Assume that DB is perpendicular to AB and DC is perpendicular to AC.
Lets prove DB and DC are congruent (that is point D is equidistant from sides of an angle â BAC
Proof
Consider triangles ΔADB and ΔADC
Both are right angle, â ABD= â ACD=90 degree
They have congruent acute angle â BAD and â CAD( since AD is angle bisector)
They share hypotenuse AD
therefore these right angle are congruent by two angle and sides and, therefore, their sides DB and DC are congruent too, as luing across congruent angles</span>
Answer:
6 cm for both sides
Step-by-step explanation:
The answer to the problem is going to be 3
Answer:
Please read the answers below.
Step-by-step explanation:
Let's calculate the four means between 100 and 135, this way:
1. Arithmetic mean:
(100 + 135)/2 = 117.5
2. Weighted mean:
We will assign equal weight to both numbers : 5
(100 * 5 + 135 * 5)/10 = (500 + 675)/10 = 1,175/10 = 117.5
3. Geometric mean:
√100 * 135 = √13,500 = 116.2 (Rounding to the next tenth)
4. Harmonic mean:
2/(1/100 + 1/135) = 2/(0.01 + 0.0074) = 114.9 (Rounding to the next tenth)
Answer:
4 1/12
Step-by-step explanation:
make all the denominators 12 so u can add them easier
2 1/12 + 2 4/12 + 3 2/12 = 7 7/12
nn subtract from the 11 2/3
11 8/12 - 7 7/12 = 4 1/12
