What is the solution to y=x+2 and x=-3

8 divided by (-1/8) please please

Nuetrik [128]

Answer: -64

Step-by-step explanation:

flip the fraction, and then change the sign so it turns into multiplication.

-8 x 8

multiply them after that.

-64

5 0

4 years ago

Alice is thinking of a number n that she wants her sister to guess. Her first clue is that two less than six times her number is

Alik [6]

Answer:

10 < 6n -2 ≤ 34

n= {3, 4, 5, 6}

Step-by-step explanation:

number

⇒ n

two less than six times the number

⇒ 6n -2

it is between ten and thirty-four (inclusive)

⇒ 10 < 6n -2 ≤ 34

we can solve it as:

10 < 6n -2 ≤ 34 ⇒ add 2 to all sides
12 < 6n ≤ 36 ⇒ divide by 6 all sides
2 < n ≤ 6
n= (2, 6]

or

n= {3, 4, 5, 6}

5 0

3 years ago

the temperature t at which water boils is inversely proportional to the number of feet F the water is above sea level. write the

Fudgin [204]

Answer:

Water temperature in an ocean varies inversely to the water’s depth. Between the depths of 250 feet and 500 feet, the formula

T

=

14

,

000

d

gives us the temperature in degrees Fahrenheit at a depth in feet below Earth’s surface. Consider the Atlantic Ocean, which covers 22% of Earth’s surface. At a certain location, at the depth of 500 feet, the temperature may be 28°F.

3 0

3 years ago

An equation of a hyperbola is given.

siniylev [52]

Answer:

a)

The vertices are $\left(3,\:0\right),\:\left(-3,\:0\right)$ .

The foci are $\left(3\sqrt{5},\:0\right),\:\left(-3\sqrt{5},\:0\right)$ .

The asymptotes are $y=2x,\:y=-2x$ .

b) The length of the transverse axis is 6.

c) See below.

Step-by-step explanation:

$\frac{\left(x-h\right)^2}{a^2}-\frac{\left(y-k\right)^2}{b^2}=1$ is the standard equation for a right-left facing hyperbola with center $\left(h,\:k\right)$ .

a)

The vertices $\:\left(h+a,\:k\right),\:\left(h-a,\:k\right)$ are the two bending points of the hyperbola with center $\:\left(h,\:k\right)$ and semi-axis a, b.

Therefore,

$\frac{x^2}{9}-\frac{y^2}{36}=1$ , is a right-left Hyperbola with $\:\left(h,\:k\right)=\left(0,\:0\right),\:a=3,\:b=6$ and vertices $\left(3,\:0\right),\:\left(-3,\:0\right)$ .

For a right-left facing hyperbola, the Foci (focus points) are defined as $\left(h+c,\:k\right),\:\left(h-c,\:k\right)$ where $c=\sqrt{a^2+b^2}$ is the distance from the center $\left(h,\:k\right)$ to a focus.

Therefore,

$\frac{x^2}{9}-\frac{y^2}{36}=1$ , is a right-left Hyperbola with $\:\left(h,\:k\right)=\left(0,\:0\right),\:a=3,\:b=6$ $c=\sqrt{3^2+6^2}= 3\sqrt{5}$ and foci $\left(3\sqrt{5},\:0\right),\:\left(-3\sqrt{5},\:0\right)$

The asymptotes are the lines the hyperbola tends to at $\pm \infty$ . For right-left hyperbola the asymptotes are: $y=\pm \frac{b}{a}\left(x-h\right)+k$