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3 years ago

What is the volume of the cone with 27 as the height and 4 as the radius?

Mathematics

1 answer:

Lady bird [3.3K]3 years ago

6 0

Answer:

V= 452.39

Step-by-step explanation

V=πr2h3=π·42·273≈452.38934

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The store has 28 notebooks in packs of 4. Three packs of notebooks are sold. How many packs of notebooks are left?

alukav5142 [94]

28/4=7x3=21 so 28-21=7 notebooks left

7 0

3 years ago

Which of the following represents the factorization of the trinomial below?<br>x2 - 6x +9

valentinak56 [21]

For this case we must factor the following expression:

$x ^ 2-6x + 9$

We must find two numbers that, when multiplied, result in 9 and when added, result in -6.

These numbers are -3 and -3.

$-3-3 = -6\\-3 * -3 = + 9$

Then, the factored expression is of the form:

$(x-3) (x-3) = (x-3) ^ 2$

Thus, the correct option is option C.

ANswer:

Option C

3 0

3 years ago

Solve each equation.)<br><br> 9+t=35

Reptile [31]

Answer:

t = 26

Step-by-step explanation:

Step 1: Subtract 9 from both sides.

$9 + t - 9 = 35 - 9$
$t = 26$

Step 2: Check if solution is correct.

$9 + 26 = 35$
$35=35$

Therefore, t = 26.

6 0

3 years ago

Read 2 more answers

Evaluate f(a + h) − f(a) for the quadratic function f(x) = x2 + 5. f(a + h) − f(a)

Butoxors [25]

$f(x)=x^2+5\\\\f(a+h)=(a+h)^2+5=a^2+2ah+h^2+5\\\\f(a)=a^2+5\\\\f(a+h)-f(a)=(a^2+2ah+h^2+5)-(a^2+5)=a^2+2ah+h^2-a^2-5=2ah+h^2$

8 0

3 years ago

The Office of Student Services at UNC would like to estimate the proportion of UNC's 28,500 students who are foreign students. I

ANEK [815]

Answer:

For the sampling distribution of the sample proportion for a sample of size 50, the mean is 0.061 and the standard deviation is 0.034.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

In this question:

$p = 0.061, n = 50$

Mean:

$\mu = p = 0.061$

Standard deviation:

$s = \sqrt{\frac{0.061*0.939}{50}} = 0.034$

For the sampling distribution of the sample proportion for a sample of size 50, the mean is 0.061 and the standard deviation is 0.034.

3 0

3 years ago