Let f(x) = x² + 6x²-x+ 5 then ,
number to be added be P
then,
f(x) = x² + 6x²-x+ 5 +P
According to the qn,
(x+3) is exactly divisible by zero then,
R=0
comparing .. we get a= -3
now by remainder theorm
R=f(a)
0=f(-3)
0=(-3)² + 6(-3)²-(-3)+ 5 + P
0= 9 + 54 + 3 + 5 + P
-71=P
therefore, -71 should be added.
Hope you understand
3/12 of the mug is not blue or red
Answer:
Step-by-step explanation:
1/2k - 3/8k.....lowest common denominator is 8
4/8k - 3/8k = 1/8k <===
Answer:
e = 4796
Step-by-step explanation:
given,
mean of five distinct positive number = 1000
median of the number = 100
100 is median means two number will be less than 100 and two number will be greater than 100.
let five number be
a , b, c, d, e
'e' should be the largest number
As 100 is median so 'c' = 100.
'a' and 'b' should be as small as possible and d should be the number nearest to 100.
As all the number are distinct so the least number be equal to 1 and 2
now d will be equal to 101 (nearest to 100)
now,
sum of the five number = 5 x 1000 = 5000
a + b + c + d + e = 5000
1 + 2 + 100 + 101 + e = 5000
e = 5000 - 204
e = 4796
hence, the largest number will be equal to e = 4796