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3 years ago

9

A farmer estimated that there were 25 gallons of water left in a tank. If this is an underestimate by 16%, how much water was ac

tually in the tank?

1 answer:

djyliett [7]3 years ago

8 0

Answer:

The actual water in the tank is 29.76 gallons.

Step-by-step explanation:

It is given that the farmer estimated amount of water is 25 gallons.

It is also given that he underestimate the water in tank by 16%.

Let the actual water in tank be x.

$(1-\frac{16}{100})x=25$

$(\frac{100-16}{100})x=25$

$84x=25\times 100$

$x=\frac{2500}{84}$

$x=29.7619$

$x\approx 29.76$

Therefore the actual water in the tank is 29.76 gallons.

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Drag the tiles to the correct boxes to complete the pairs.

Ne4ueva [31]

Answer:

Part 1) $-1.25$ -------> $2.75/(-2.2)$

Part 2) $-4\frac{1}{3}$ --------> $(-2\frac{3}{5}) / (\frac{3}{5})$

Part 3) $\frac{2}{3}$ ------> $(-\frac{10}{17}) / (-\frac{15}{17})$

Part 4) $3$ ------> $(2\frac{1}{4}) / (\frac{3}{4})$

Step-by-step explanation:

Part 1) we have

$2.75/(-2.2)$

To calculate the division problem convert the decimal number to fraction number

$2.75=275/100\\ -2.2=-22/10$

so

$(275/100)/(-22/10)$

Remember that

Since division is the opposite of multiplication, you can turn this division problem into a multiplication problem by multiplying the top fraction by the reciprocal of the bottom fraction

$(275/100)/(-22/10)=(275/100)*(-10/22)=-(275*10)/(22*100)=-(275)/(220)$

Simplify

Divide by 22 both numerator and denominator

$-(275)/(220)=-125/100=-1.25$

Part 2) we have

$(-2\frac{3}{5}) / (\frac{3}{5})$

To calculate the division problem convert the mixed number to an improper fraction

$(-2\frac{3}{5})=-\frac{2*5+3}{5}=-\frac{13}{5}$

so

$(-\frac{13}{5}) / (\frac{3}{5})$

Since division is the opposite of multiplication, you can turn this division problem into a multiplication problem by multiplying the top fraction by the reciprocal of the bottom fraction

$(-\frac{13}{5}) / (\frac{3}{5})=(-\frac{13}{5})*(\frac{5}{3})=-\frac{13*5}{5*3}=-\frac{13}{3}$

Convert to mixed number

$-\frac{13}{3}=-(\frac{12}{3}+\frac{1}{3})=-4\frac{1}{3}$

Part 3) we have

$(-\frac{10}{17}) / (-\frac{15}{17})$

Since division is the opposite of multiplication, you can turn this division problem into a multiplication problem by multiplying the top fraction by the reciprocal of the bottom fraction

$(-\frac{10}{17}) / (-\frac{15}{17})=(-\frac{10}{17})*(-\frac{17}{15})=\frac{10*17}{17*15}=\frac{10}{15}$

Simplify

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Part 4) we have

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To calculate the division problem convert the mixed number to an improper fraction

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so

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Since division is the opposite of multiplication, you can turn this division problem into a multiplication problem by multiplying the top fraction by the reciprocal of the bottom fraction

$(\frac{9}{4}) / (\frac{3}{4})=(\frac{9}{4})*(\frac{4}{3})=\frac{9*4}{4*3}=\frac{9}{3}=3$

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