Answer:
If your form is correct (b)
Answer:
Torque, 
Explanation:
It is given that,
Length of the wrench, l = 0.5 m
Force acting on the wrench, F = 80 N
The force is acting upward at an angle of 60.0° with respect to a line from the bolt through the end of the wrench. We need to find the torque is applied to the nut. We know that torque acting on an object is equal to the cross product of force and distance. It is given by :



So, the torque is applied to the nut is 34.6 N.m. Hence, this is the required solution.
Answer:
70 revolutions
Explanation:
We can start by the time it takes for the driver to come from 22.8m/s to full rest:

The tire angular velocity before stopping is:

Also its angular decceleration:

Using the following equation motion we can findout the angle it makes during the deceleration:

where
= 0 m/s is the final angular velocity of the car when it stops,
= 114rad/s is the initial angular velocity of the car
= 14.75 rad/s2 is the deceleration of the can, and
is the angular distance traveled, which we care looking for:

or 440/2π = 70 revelutions
Resultant force= (2*6^2)^(1/2)
=8.5m/s
answer is B.
Answer:
0 N
Explanation:
Applying,
F = qvBsin∅................. Equation 1
Where F = Force on the charge, q = charge, v = Velocity, B = magnetic charge, ∅ = angle between the velocity and the magnetic field.
From the question,
Given: q = 4.88×10⁻⁶ C, v = 265 m/s, B = 0.0579 T, ∅ = 0°
Substitute these values into equation 1
F = ( 4.88×10⁻⁶)(265)(0.0579)(sin0)
Since sin0° = 0,
Therefore,
F = 0 N