Answer:
V = 9.682 × 10^(-6) V
Explanation:
Given data
thick = 190 µm
wide = 4.20 mm
magnitude B = 0.78 T
current i = 32 A
to find out
Calculate V
solution
we know v formula that is
V = magnitude× current / (no of charge carriers ×thickness × e
here we know that number of charge carriers/unit volume for copper = 8.47 x 10^28 electrons/m³
so put all value we get
V = magnitude× current / (no of charge carriers ×thickness × e
V = 0.78 × 32 / (8.47 x 10^28 × 190 × 1.602 x 10^(-19)
V = 9.682 × 10^(-6) V
Answer:
3) flow of electrons, if im correct
Answer:
1.89mol
Explanation:
The entropy change during free expansion is express as
![S_{f}-S_{i}=nRln(\frac{V_{F}}{V_{I}})\\](https://tex.z-dn.net/?f=S_%7Bf%7D-S_%7Bi%7D%3DnRln%28%5Cfrac%7BV_%7BF%7D%7D%7BV_%7BI%7D%7D%29%5C%5C)
Where S is the entropy of the system,
n is the amount of mole
R is the gas constant = 8.314 and
V is the volume occupied at the initial and final stage
since the process is n adiabatic free expansion, the entropy of the system is constant. Hence we can re-write the equation as
![S=nRln(\frac{V_{F}}{V_{I}})\\](https://tex.z-dn.net/?f=S%3DnRln%28%5Cfrac%7BV_%7BF%7D%7D%7BV_%7BI%7D%7D%29%5C%5C)
where the
and ![V_{f}=2v+v=3v\\](https://tex.z-dn.net/?f=V_%7Bf%7D%3D2v%2Bv%3D3v%5C%5C)
and
Now if we substitute in values we arrive at
![17.28=(8.314)n*ln(\frac{3v}{v} )\\17.28=(8.314)n*ln(3 )\\17.28=(8.314)n*1.0986\\n=\frac{17.28}{8.314*1.0989}\\n=1.89 mole\\](https://tex.z-dn.net/?f=17.28%3D%288.314%29n%2Aln%28%5Cfrac%7B3v%7D%7Bv%7D%20%29%5C%5C17.28%3D%288.314%29n%2Aln%283%20%29%5C%5C17.28%3D%288.314%29n%2A1.0986%5C%5Cn%3D%5Cfrac%7B17.28%7D%7B8.314%2A1.0989%7D%5C%5Cn%3D1.89%20mole%5C%5C)
The answer to the question can charging by friction occur only in solids is no. not at all. the static charge generated by following fluids can be hazardous. just as the static discharge when you touch a doorknob produces a spark, lightening is the spark from the static charge built up in the atmosphere.