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juin [17]
3 years ago
7

Air at 20°c (1 atm) enters into a 5-mm-diameter and 10-cm long circular tube at an average velocity of 5.4 m/s. the tube wall is

maintained at a constant surface temperature of 160°c. determine the convection heat transfer coefficient and the outlet mean temperature. evaluate the air properties at 50°c. the properties of air at 50°c are: ρ = 1.092 kg/m3 μ = 1.963*10-5 kg/m∙s k = 0.02735 w/m∙k cp = 1007 j/kg∙k v = 1.798 *10−5 m2/s μs = 2.420*10−5 kg/m∙s pr = 0.7228
Physics
1 answer:
velikii [3]3 years ago
8 0
Im really sorry. pls dont report this comment. i need points. I have a question but I am bad at english and I cant answer peoples
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During a free fall Swati was accelerating at -9.8m/s2. After 120 seconds how far did she travel? Use the formula =1/2 *
marta [7]
Distance fallen = 1/2 ( V initial + V final ) *t
We know
a = -9.8 m/s2
t=120s

To find distance fallen, we need to find V final
Use the equation
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Substitute known values
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=106,560 m

This way plugging into distance equation is actually the long way. A faster way is to plug the values into
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We won't need to find V final using another equation.

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4 0
3 years ago
Buoyancy increases with the increase in the density of a) Submerged body b) Fluid​
AlekseyPX

Answer:

Submerged body

Explanation:

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4 0
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