Question

Find the 14th term of the geometric sequence 3,6,12,24.

Answer 1

An=a1(r)^(n-1)
a1=first term
r=common rati

common ratio is a term divded by previous term
6/3=2
r=2

first term is 3

an=3(2)^(n-1)
14th term
a14=3(2)^(14-1)
a14=3(2)^13
a14=3(8192)
a14=24576

the 14th term is 24576