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never
[62]
4 years ago
12
Find the 14th term of the geometric sequence 3,6,12,24.
Mathematics
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answer:
jekas
[21]
4 years ago
5
0
An=a1(r)^(n-1)
a1=first term
r=common rati
common ratio is a term divded by previous term
6/3=2
r=2
first term is 3
an=3(2)^(n-1)
14th term
a14=3(2)^(14-1)
a14=3(2)^13
a14=3(8192)
a14=24576
the 14th term is 24576
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