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Rudiy27
3 years ago
11

there are 32 students in 4th grade class.Each table in the classroom seats 6 students.how many tables will be needed

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
3 0
This question wants you to divide 32 tables by 6 students which is 5.3333. Since 5 tables is not enough, 6 tables are needed.
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What is the root of the polynomial equation x(x-2)(x+3) = 18? Use a graphing calculator and a system of equations.
Trava [24]

9514 1404 393

Answer:

  x = 3

Step-by-step explanation:

The equation can be rewritten to make use of the graphing calculator's ability to identify function zeros:

  x(x -2)(x +3) -18 = 0

The attached shows x = 3 is the only real solution.

_____

We're not sure what "system of equations" is intended. Perhaps it is ...

  y = 18

  y = x(x -2)(x +3)

To create the expression we graphed, we effectively subtracted the first equation from the second.

3 0
3 years ago
Please help what is for 1/2 x 1 2/3
matrenka [14]
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7 0
3 years ago
Read 2 more answers
If n+h/5=f+9/9, then n/5=
Ann [662]
------------------------------------------------------------------
Question
------------------------------------------------------------------
\boxed { \frac{n+h}{5}  =  \frac{f+9}{9}}

------------------------------------------------------------------
Split the fraction on the left
------------------------------------------------------------------
\boxed { \frac{n}{5} + \frac{h}{5}  = \frac{f + 9}{9}}

------------------------------------------------------------------
Take away h/5 from both sides
------------------------------------------------------------------
\boxed { \frac{n}{5}  = \frac{f+9}{9} - \frac{h}{5}}

------------------------------------------------------------------
Change the denominator to be the same
------------------------------------------------------------------
\boxed { \frac{n}{5} = \frac{5f+45}{45} - \frac{9h}{45}}

------------------------------------------------------------------
Put it into single fraction
------------------------------------------------------------------
\boxed { \frac{n}{5} = \frac{5f+45-9h}{45} }

-------------------------------------------------------------------
Rearrange (This step may not be necessary)
------------------------------------------------------------------
\boxed {\frac{n}{5} = \frac{5f-9h+ 45}{45} }


\bf \Longrightarrow \ Answer \ : \boxed {\boxed {\frac{n}{5} = \frac{5f-9h+ 45}{45} }}

6 0
3 years ago
Can anyone help me. Please
faust18 [17]

Answer:

how can I help?

Step-by-step explanation:

with what?

5 0
3 years ago
an isosceles triangle has congruent sides of 20cm. the base is 10cm. find the height of the triangle.​
dolphi86 [110]

Answer:

\large\boxed{A_\triangle=25\sqrt{15}\ cm^2}

Step-by-step explanation:

Look at the picture.

The formula of an area of a triangle:

A_\triangle=\dfrac{bh}{2}

<em>b</em><em> - base</em>

<em>h</em><em> - height</em>

<em />

We need a length of a height.

Use the Pythagorean theorem:

leg^2+leg^2=hypotenuse^2

We have:

leg=5,\ leg=h,\ hypotenuse=20

Substitute:

5^2+h^2=20^2

25+h^2=400             <em>subtract 25 from both sides</em>

h^2=375\to h=\sqrt{375}\\\\h=\sqrt{(25)(15)}\\\\h=\sqrt{25}\cdot\sqrt{15}\\\\h=5\sqrt{15}\ cm

Calculate the area:

A_\triangle=\dfrac{(10)(5\sqrt{15})}{2}=\dfrac{50\sqrt{15}}{2}=25\sqrt{15}\ cm^2

8 0
3 years ago
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