X^3 + 5^3
(x+5)x(x^2-X x 5+5^2)
(x+5)x(x^2 -5x+5^2)
(x+5)x(x^2 -5x+25)
(x+5) x (x^2 -5x+25)
If length of rectangle is 8 cm, breadth is 4 cm, side of square is 3 cm, base of triangle is 3 cm, then the area of figure will be 48.5
.
Given that length of rectangle is 8 cm, Breadth of rectangle is 4 cm,side of square is 3 cm,base of right angled triangle is 3 cm,height of triangle is 5 cm.
Area of figure=Area of rectangle+Area of square+Area of triangle
Area of rectangle=length*breadth
Area of square=Side*Side
Area of triangle=1/2 *Base*Height
Area of figure=8*4+3*3+1/2 *3*5
=32+9+1/2 *15
=41+15/2
=(82+15)/2
=97/2
=48.5 
Hence if length of rectangle is 8 cm, breadth is 4 cm, side of square is 3 cm, base of triangle is 3 cm, then the area of figure will be 48.5
.
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Answer:

Step-by-step explanation:
we have

step 1
Solve (90+1)

step 2
Solve 0.0698(91)

step 3
Solve sin (6.3518)

step 4
Solve 105(0.11063)

step 5
Solve 11.616 + 105

Answer:
20
Step-by-step explanation:
8+3+5+1+3=20
rounded up at .50 or higher