(x,y) so you start at the orgin and go down two because it's negative. then you go right six and plot your point.
negative number - down or left
positive number - up or right
Hey there! :)
To find an equation of a line that passes through (5, 1) and has a slope of 2, we'll need to plug our known variables into the slope-intercept equation.
Slope-intercept equation : y = mx + b ; where m=slope, b=y-intercept
Since we're already given the slope, all we really need to do is find the y-intercept.
We can do this by plugging our known values into the slope-intercept equation.
y = mx + b
Since we're trying to find "b," we need to plug in "y, m, x" into our formula.
(1) = (2)(5) + b
Simplify.
1 = 10 + b
Subtract 10 from both sides.
1 - 10 = b
Simplify.
-9 = b
So, our y-intercept is 9!
Now, we can very simply plug our known values into slope-intercept form.
y = mx + b
y = 2x - 9 → final answer
~Hope I helped!~
Answer:
A box plot is drawn with end points at 24 and 49.The box extends from 28 to 44 and a vertical line is drawn inside the box at 34.
Step-by-step explanation:
Ordering the data given :
24,28,32,34,40,44,49
We can calculate the 5 number summary required to give the appropriate boxplot that can be produced :
Minimum = 24
Maximum = 49
Median = 1/2(n+1)th term
n = 7
Median = 1/2(8) = 4th term
Median = 34
Lower quartile, Q1 = 1/4(n+1)th term
n = 7
1/4(8) = 2nd term
Q1 = 28
Upper quartile : 3/4(n+1)th term
n = 7
Q3 = 3/4(8) = 6th term
Q3= 44
Answer:
EG is 19 units
Step-by-step explanation:
Let us solve the question
∵ Lines CD and EF intersected at point G
∴ CD = CG + GD
∴ EF = EG + GF
∵ Line EF bisects line CD
→ That means G is the midpoint of CD
∴ CG = GD
∵ CG = 5x -1
∵ GD = 7x - 13
→ Equate them to find x
∴ 7x - 13 = 5x -1
→ Add 13 to both sides
∴ 7x -13 + 13 = 5x - 1 + 13
∴ 7x = 5x + 12
→ Subtract 5x from both sides
∴ 7x - 5x = 5x - 5x + 12
∴ 2x = 12
→ Divide both sides by 2
∴ 
∴ x = 6
∵ EF = 6x - 4
→ Substitute x by 6 to find its length
∴ EF = 6(6) - 4 = 36 - 4
∴ EF = 32
∵ EF = EG + GF
∵ GF = 13
∴ 32 = EG + 13
→ Subtract 13 from both sides
∵ 32 - 13 = EG + 13 - 13
∴ 19 = EG
∴ EG = 19 units
Perimeter of a rectangle can be represented by 2* length + 2 * width
We can represent the width with the variable x
We can represent the length by the expression 3x-1
So, now we can make a forumla and solve
2(3x-1) + 2(x) = 30
6x-2+2x = 30
8x = 32
x = 4 is the width of the rectange.
Now we find the length
3(4)-1
11 = Length