Answer:
Step-by-step explanation:
Given
Hoop, Uniform Solid Cylinder, Spherical shell and a uniform Solid sphere released from Rest from same height
Suppose they have same mass and radius
time Period is given by
,where h=height of release
a=acceleration

Where I=moment of inertia
a for hoop


a for Uniform solid cylinder


a for spherical shell


a for Uniform Solid


time taken will be inversely proportional to the square root of acceleration




thus first one to reach is Solid Sphere
second is Uniform solid cylinder
third is Spherical Shell
Fourth is hoop

It is true only whenever x tends to 0(zero)
it is not importent that x be in radian or in degree.
A square has 4 equal sides which make up the perimeter.
Therefore the length of one side = (16x + 32y) / 4 = 4x + 8y Answer
Answer:
W = (P - 2L)/2 = (28- 2*8)/2 = 6
Where W is the width, P is the perimeter and L is the length of the garden.
Step-by-step explanation:
Since the equations are not given, i will try to come up with the similar equation than the ne that was the correct option in this exercise.
You can obtain the perimeter of a rectangle by summing the length of its four sides. Thus, the perimeter of the garden, lets call it P, is 2W + 2L, where W denotes the width and L the length. Since Nancy knows the perimeter, in order to calculate the width she can substract from it 2L (which is also known), and divide by 2 to obtain W, thus
W = (P - 2L)/2
If we reemplace P by 28 and L by 8, we obtain
W = (28-8*2)/2 = (28-16)/2 ) = 12/2 = 6.