Answer:
The standard deviation of the sampling distribution of sample means would be 0.8186.
Step-by-step explanation:
We are given that
Mean of population=23.2 pounds
Standard deviation of population=6.6 pounds
n=65
We have to find the standard deviation of the sampling distribution of sample means.
We know that standard deviation of the sampling distribution of sample means
=
Using the formula
The standard deviation of the sampling distribution of sample means
=
Hence, the standard deviation of the sampling distribution of sample means would be 0.8186.
Answer:
0.0016283
Step-by-step explanation:
Given that:
Proportion of defective bulbs, p = 30% = 0.3
Sample size, n = 19 bulbs
Probability that the lot will pass inspection :
P(none of the 19 is defective) Or P(only one of the 19 is defective)
P(none of the 19 is defective) = (1 - p) ^n = (1 - 0.3)^19 ; 0.7^19
0.7^19 = 0.0011398
P(only one of the 19 is defective) :
P(1 defective) * P(18 not defective )
(0.3) * (1 - 0.3)^18
0.3 * 0.7^18
0.3 * 0.001628413597910449 = 0.0004885
Hence,
P(none of the 19 is defective) + P(only one of the 19 is defective)
0.0011398 + 0.0004885) = 0.0016283
Assuming he had not dealt with the bank offering plan B before, he has nothing deposited two years back. Hence plan B only gives him only 0.2% annual interest for his deposit.
Plan A gives 0.25% for his deposit all the time.
So plan A is more advantageous.
For durations,
To reach $1,000,000 from $100,000, the money needs to grow 10 fold, or
(1+i)^n=10
n=log(10)/log(1+i).
So for plan A:
n=log(10)/log(1.0025)=922.18 years, while for
plan B
n=log(10)/log(1.0020)=1152.44 years.
Hope the bank(s) still exist at that time.
Answer: approximately normal (c) trust me-khan academy
Step-by-step explanation:
3d is the answer if I am wrong please let me know
