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malfutka [58]
3 years ago
12

True or false every whole number is a multiple of 1?

Mathematics
1 answer:
jenyasd209 [6]3 years ago
3 0
Every whole number is not a factor of 1. However, 1 is a factor of every whole number
You might be interested in
What's the equivalent fraction to 32/41
Lapatulllka [165]
64/82
just double your fraction and it'll still be equivalent to it.
32 x 2 = 64
41 x 2 = 82
5 0
3 years ago
Han ran 10 meters in 2.7 seconds. Priya ran 10 meters in 2.4 seconds. How long would it take han to run 50 meters.
Lina20 [59]

Hans would take 13.5 seconds to run 50 meters

Priya would take 12 seconds to run 50 meters

--------------------------------------------------------------------------------

Since they each ran 10 meters for a certain amount of time you would multiply the seconds by 5 since 10x5=50

When you do that you get

13.5 for Han's time by multiplying 2.7x5=13.5

and

12 seconds for Priya's time by multiplying 2.4x5

3 0
3 years ago
How many permutations of the 26 letters of the English alphabet do not contain any of the strings fish, rat, or bird
NARA [144]

The number of permutations of the 26 letters of the English alphabet that do not contain any of the strings fish, rat, or bird is 402619359782336797900800000

Let

\mathcal{E}=\{\text{All lowercase letters of the English Alphabet}\}\\\\B=\overline{\{b,i,r,d\}} \cup \{bird\}\\\\F=\overline{\{f,i,s,h\}} \cup \{fish\}\\\\R=\overline{\{r,a,t\}} \cup \{rat\}\\\\FR=\overline{\{f,i,s,h,r,a,t\}} \cup \{fish,rat\}

Then

Perm(\mathcal{E})=\{\text{All orderings of all the elements of } \mathcal{E}\}\\\\Perm(B)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing bird}\}\\\\Perm(F)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing fish}\}\\\\Perm(R)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing rat}\}\\\\Perm(FR)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing both fish and rat}\}\\

Note that since

F \cap R=\varnothing, Perm(F)\cap Perm(R)\ne \varnothing

But since

B \cap R \ne \varnothing, Perm(B)\cap Perm(R)= \varnothing

and

B \cap F \ne \varnothing , Perm(B)\cap Perm(F)= \varnothing

Since

|\mathcal{E} |=26 \text{, then, } |Perm(\mathcal{E})|=26! \\\\|B|=26-4+1=23 \text{, then, } |Perm(B)|=23!\\\\|F|=26-4+1=23 \text{, then, } |Perm(F)|=23!\\\\|R|=26-3+1=24 \text{, then, } |Perm(R)|=24!\\\\|FR|=26-7+2=21 \text{, then, } |Perm(FR)|=21!\\

where |Perm(X)|=\text{number of possible permutations of the elements of X taking all at once}

and

|Perm(F) \cup Perm(R)| = |Perm(F)| + |Perm(R)| - |Perm(FR)|\\= 23!+24!- 21! \text{ possibilities}

What we are looking for is the number of permutations of the 26 letters of the alphabet that do  not contain the strings fish, rat or bird, or

|Perm(\mathcal{E})|-|Perm(B)|-|Perm(F)\cup Perm(R)|\\= 26!-23!-(23!+24!- 21!)\\= 402619359782336797900800000 \text{ possibilities}

This link contains another solved problem on permutations:

brainly.com/question/7951365

6 0
2 years ago
Out of the 1236 employees who work for a particular company, 748 of them work in an office. One employee is selected every month
Aliun [14]

Answer:

458

Step-by-step explanation:

3 0
3 years ago
Antar is flying a triangular-shaped kite. it has a height of 4 1/2 feet and a base of 5 3/4 feet. what is the area of Antar's ki
Natasha_Volkova [10]
The area of a triangle is \frac{1}{2}bh \frac{1}{2}(4.5feet)(5.75feet) and that would equal 12.9375 feet²
6 0
3 years ago
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