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Alex73 [517]
3 years ago
5

A gardener has 46ft of fencing to be used to enclose a rectangular garden that has a border 2 feet wide surrounding it. If the l

ength of the garden is to be twice its width, what will be the dimensions of the garden?
Mathematics
1 answer:
LekaFEV [45]3 years ago
7 0
Let the width be x, then the length is 2x
2(x + 4 + 2x + 4) = 46
(3x + 8) = 46/2 = 23
3x = 23 - 8 = 15
x = 15/3 = 5 ft

Therefore, width is 5 feet and length is 2(5) = 10 feet
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A display case for the artifact is in the shape of a cube. Each side of the display case is three times longer than the width ww
Katena32 [7]
A cube is a 3d object bounded by  6 square faces. 

Each side of the display case is 3 times longer than the width of the artifact.

width of the artifact = w
side of the cube = 3w

<span>a. Write an expression for the volume of the case.
 volume of a cube is the measure of its side raised to the power of 3.

Volume = (3w)</span>³

<span>Volume = 27w</span>³<span>

</span>
6 0
3 years ago
A photograph is reduced by a scale factor of 3/8 . If the original length of the photograph was 20 inches, what is the length of
Ksju [112]
To solve this problem you must apply the proccedure shown below:

 1. You have that the following information given in the problem above: The<span> photograph is reduced by a scale factor of 3/8 and the original had a length of 20 inches, 

 2- Therefore you have:

 length=20 inches-</span>(20 inches x 3/8)<span>
 length=20 inches-7.5 inches
 length=12.5 inches

 3- Then, as you can see, the answer is: 12.5 inches.</span>
8 0
3 years ago
−2x=x^2−6
Iteru [2.4K]

Step-by-step explanation:

Example 1

Solve the equation x3 − 3x2 – 2x + 4 = 0

We put the numbers that are factors of 4 into the equation to see if any of them are correct.

f(1) = 13 − 3×12 – 2×1 + 4 = 0 1 is a solution

f(−1) = (−1)3 − 3×(−1)2 – 2×(−1) + 4 = 2

f(2) = 23 − 3×22 – 2×2 + 4 = −4

f(−2) = (−2)3 − 3×(−2)2 – 2×(−2) + 4 = −12

f(4) = 43 − 3×42 – 2×4 + 4 = 12

f(−4) = (−4)3 − 3×(−4)2 – 2×(−4) + 4 = −100

The only integer solution is x = 1. When we have found one solution we don’t really need to test any other numbers because we can now solve the equation by dividing by (x − 1) and trying to solve the quadratic we get from the division.

Now we can factorise our expression as follows:

x3 − 3x2 – 2x + 4 = (x − 1)(x2 − 2x − 4) = 0

It now remains for us to solve the quadratic equation.

x2 − 2x − 4 = 0

We use the formula for quadratics with a = 1, b = −2 and c = −4.

We have now found all three solutions of the equation x3 − 3x2 – 2x + 4 = 0. They are: eftirfarandi:

x = 1

x = 1 + Ö5

x = 1 − Ö5

Example 2

We can easily use the same method to solve a fourth degree equation or equations of a still higher degree. Solve the equation f(x) = x4 − x3 − 5x2 + 3x + 2 = 0.

First we find the integer factors of the constant term, 2. The integer factors of 2 are ±1 and ±2.

f(1) = 14 − 13 − 5×12 + 3×1 + 2 = 0 1 is a solution

f(−1) = (−1)4 − (−1)3 − 5×(−1)2 + 3×(−1) + 2 = −4

f(2) = 24 − 23 − 5×22 + 3×2 + 2 = −4

f(−2) = (−2)4 − (−2)3 − 5×(−2)2 + 3×(−2) + 2 = 0 we have found a second solution.

The two solutions we have found 1 and −2 mean that we can divide by x − 1 and x + 2 and there will be no remainder. We’ll do this in two steps.

First divide by x + 2

Now divide the resulting cubic factor by x − 1.

We have now factorised

f(x) = x4 − x3 − 5x2 + 3x + 2 into

f(x) = (x + 2)(x − 1)(x2 − 2x − 1) and it only remains to solve the quadratic equation

x2 − 2x − 1 = 0. We use the formula with a = 1, b = −2 and c = −1.

Now we have found a total of four solutions. They are:

x = 1

x = −2

x = 1 +

x = 1 −

Sometimes we can solve a third degree equation by bracketing the terms two by two and finding a factor that they have in common.

6 0
3 years ago
Read 2 more answers
Mr. Wells tells his class of 24 that when
abruzzese [7]

Answer:

About 10 people

Step-by-step explanation:

40% is 0.4. 24 × 0.4 = 9.6 which is approximately 10.

3 0
3 years ago
Look at picture! IM GIVING ALL THE POINTS!
stepan [7]

Answer:

Are we supposed to fill in the blanks of the equation?

5 0
3 years ago
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