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Vera_Pavlovna [14]
3 years ago
8

Evaluate the expression of c=7-x

Mathematics
1 answer:
Novay_Z [31]3 years ago
8 0
Solve for c.<span><span>c−7</span>=x</span>Step 1: Add 7 to both sides.<span><span><span>c−7</span>+7</span>=<span>x+7</span></span><span>c=<span>x+7</span></span>so the answer is:<span>c=<span>x+<span>7</span></span></span>
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What is the monthly payment for $280000 mortgage with an interest of 6% compounded monthly for 20 years?
Snezhnost [94]
The formula of the present value of an annuity ordinary is
Pv=pmt [(1-(1+r/k)^(-kn))÷(r/k)]
Pv present value 280000
PMT monthly payment?
R interest rate 0.06
K compounded monthly 12
N time 20 years
Solve the formula for PMT
PMT=pv÷[(1-(1+r/k)^(-kn))÷(r/k)]
PMT=280,000÷((1−(1+0.06÷12)^(
−12×20))÷(0.06÷12))
=2,006.01
4 0
3 years ago
The weight y of a object on Jupiter is proportional to the weight x of the object on earth. An object that weighs 150 ponds on e
mario62 [17]

Answer:

5.02 pounds

Step-by-step explanation:

y = k*x

Where,

y = weight of a object on Jupiter

x = weight of the object on earth

k = constant of proportionality

An object that weighs 150 ponds on earth would weigh 378.2 ponds on Jupiter.

y = k*x

378.2 = k*150

378.2 = 150k

k = 378.2/150

= 2.5213

Approximately k = 2.52

determine how Much a rock that weigh 12.64 on Jupiter would weigh on earth

y = k*x

12.64 = 2.52*x

12.64 = 2.52x

x = 12.64 / 2.52

= 5.0159

Approximately x = 5.02 pounds

6 0
3 years ago
Evaluate the line integral in Stokes? Theorem to evaluate the surface integral integrate S ( x F) n dS. Assume that n is in the
gtnhenbr [62]

Answer:

Step-by-step explanation:

Consider that F(x,y,z) = (x + y, y + z, z + z)

r(t)=(cos t,4sint,\sqt{5}cost)\\r'(t)=(-sint,4cost,-\sqrt{5}sint)\\F(r(t))=[tex]\int\limits^{2\pi}_0 {F(r(t))r'(t)} \, dt \\\\=\int\limits^{2\pi}_0(cost+4sint,4sint+\sqrt{5}cost+cost)(-sint,4cost,-\sqt{5}sint)dt\\\\=\int\limits^{2\pi}_0(-sintcost-4sin^2t+16costsint+4\sqrt{5}cos^2t-5sintcost-\sqrt{5}sintcost)dt\\\\=\int\limits^{2\pi}_0(10sintcost-4sin^2t+4\sqrt{5}cos^2t-\sqrt{5}sintcost)dt\\\\=\int\limits^{2\pi}_0((10-\sqrt{5})sintcost-(4+4+\sqrt{5})sin^2t+4\sqrt{5})dt\\\\(10-\qrt{5})(0)-(4+4+\sqrt{5}(\pi)+4\sqrt{5}(2\pi)\\\\(\sqrt{5}-1)4\pi)[/tex]

6 0
3 years ago
I fixed the question need help​
STatiana [176]

Answer:

D

Step-by-step explanation:

90-33=57

57-1=56

56/2=28

28

8 0
3 years ago
What does this equal​
Anton [14]
In simplify the expression =
1.56 • 10^52 + 3.5 • 10^48
5 0
3 years ago
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