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3 years ago

What do we call the time it take to travel around the sun one time? -Astronomy Class

Chemistry

1 answer:

Tamiku [17]3 years ago

7 0

traslation is called when a object take a travel around the sun

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During a reaction, the enthalpy of formation of an intermediate is 34 kJ/mol. During the reaction, 4 moles of the intermediate a

Lapatulllka [165]

The enthalpy change for the formation step of this intermediate is 136 kJ/mol.

<h3>What is the enthalpy?</h3>

The enthalpy of reaction can be obtained from the enthalpies of formation of the species involved. The enthalpy of reaction is the heat evolved or absorbed in a reaction.

Thus, the enthalpy change for the formation step of this intermediate is 4 * 34 kJ/mol = 136 kJ/mol.

Learn more about enthalpy change:brainly.com/question/4526346

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7 0

2 years ago

How many g are equal to 345.7mg?

Mumz [18]

Answer:

0,3457 grams equal to 345.7mg

Explanation:

1000 mg-------1 g

345.7mg------x= (345.7mgx 1 g)/1000mg= <em>0,3457 g</em>

4 0

3 years ago

Read 2 more answers

How do whales, bats, and dolphins use echolocation?

Nataly [62]

I feel like all of them are true

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3 years ago

Read 2 more answers

The mass of an average blueberry is 0.75 g and the of am automoblie is 2.0 x 10 to the 3 Kg. Find the number of automobiles whos

Paul [167]

Answer : The number of automobiles needed are, $2.26\times 10^{17}$

Explanation :

First we have to calculate the mass of blueberries.

As, 1.0 mole of blueberries contains $6.022\times 10^{23}$ blueberries

So, 0.75 grams of blueberries contains $0.75g\times 6.022\times 10^{23}=4.52\times 10^{23}g$ blueberries

Mass of blueberries = $4.52\times 10^{23}g$

Now we have to calculate the number of automobiles needed.

Number of automobiles needed = $\frac{4.52\times 10^{23}g}{2.0\times 10^{3}kg}$

Number of automobiles needed = $\frac{4.52\times 10^{23}g}{2.0\times 10^{3}\times 10^{3}g}$

Number of automobiles needed = $2.26\times 10^{17}$

Thus, the number of automobiles needed are, $2.26\times 10^{17}$

8 0

3 years ago

A bird flies 3.7 meters in 46 seconds, what is its speed?<br> v=<br> d=<br> t=

k0ka [10]

Answer:

speed = 3.7/46 = 0.080m/s

d= 3.7m

t= 46s

Explanation:

7 0

3 years ago