Answer:
C)
the potential energy is increasing through steps A & B, then decreases at C.
Explanation:
That only 250 warhead are needed to put the earth in nuclear winter
A Tsar Bomba (nuke with highest yield of 100,000 megatons developed by the Russians)in Tokyo results in 12 million dead instantly and a further 5 million in slow death.
Only the supergiants (US,Soviet Union,China,India,Uk,France,Pakistan,Israel and North K) have nukes with a fewer number of countries in the nuclear triad “hub”(US,Soviets,China,India) therefore these posses an unfair disadvantage.
Avearage nuke yield is 100 megatons which can wipe out a whole country.
They are not effective as one would use them unless they want to watch WW3 from their TV.
They produce high amount of radiation when you make them
Once produced they take a long time to dismantle.
I know everything about nukes so don’t hesitate to ask me about the topic:)
Answer: 8.57 ml of KOH is required to reach the equivalence point.
Explanation:
To calculate the volume of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is KOH.
We are given:
Putting values in above equation, we get:
Thus 8.57 ml of KOH is required to reach the equivalence point.
The –OH+ group is most acidic proton in ln-OH as shown in figure (a). The proton is circled in the figure.
The stabilisation of the conjugate base produced is stabilises due to resonance factor. The possible resonance structures are shown in figure (b).
The acidity of a protonated molecule depends upon the stabilisation of the conjugate base produced upon deprotonation. The conjugate base of ln-OH is shown in figure (a).
The possible resonance structures are shown in figure (b). As the number of resonance structures of the conjugate base increases the stabilisation increases. Here the unstable quinoid (unstable) form get benzenoid (highly stable) form due to the resonance which make the conjugate base highly stabilise.
Thus the most acidic proton is assigned in ln-OH and the stability of the conjugate base is explained.
Moles = mass / molar mass
<span>moles P = 0.422 g / 30.97 g/mol = 0.01363 mol </span>
<span>moles O = (0.967 g - 0.422g) / 16.00 g/mol = 0.03406 moles </span>
<span>So ratio moles P : moles O </span>
<span>= 0.01363 mol : 0.03406 mol </span>
<span>Divide each number in the ratio by the smallest number </span>
<span>(0.01363 / 0.01363) : (0.03406 / 0.01363) </span>
<span>= 1 : 2.5 </span>
<span>The empirical formula needs to be the smallest whole number ratio of atoms in the molecules. Since you have a non-whole number, multiply the ratio by the smallest number needed to make both number whole numbers. In this case x 2 </span>
<span>2 x (1 : 2.5) </span>
<span>= 2 : 5 </span>
