Answer:
[Ag⁺] = 5.0x10⁻¹⁴M
Explanation:
The product solubility constant, Ksp, of the insoluble salts PbI₂ and AgI is defined as follows:
Ksp(PbI₂) = [Pb²⁺] [I⁻]² = 1.4x10⁻⁸
Ksp(AgI) = [Ag⁺] [I⁻] = 8.3x10⁻¹⁷
The PbI₂ <em>just begin to precipitate when the product [Pb²⁺] [I⁻]² = 1.4x10⁻⁸</em>
<em />
As the initial [Pb²⁺] = 0.0050M:
[Pb²⁺] [I⁻]² = 1.4x10⁻⁸
[0.0050] [I⁻]² = 1.4x10⁻⁸
[I⁻]² = 1.4x10⁻⁸ / 0.0050
[I⁻]² = 2.8x10⁻⁶
<h3>[I⁻] = 1.67x10⁻³</h3><h3 />
So, as the [I⁻] concentration is also in the expression of Ksp of AgI and you know concentration in solution of I⁻ = 1.67x10⁻³M:
[Ag⁺] [I⁻] = 8.3x10⁻¹⁷
[Ag⁺] [1.67x10⁻³] = 8.3x10⁻¹⁷
<h3>[Ag⁺] = 5.0x10⁻¹⁴M</h3>
Answer:
vigorous
Explanation:
As you go down group one of the periodic table, the reactions become and more vigorous.
Pressure of the gas inside the container is 662.59 torr.
<h3>What is ideal gas law?</h3>
The ideal gas law (PV = nRT) connects the macroscopic characteristics of ideal gases. An ideal gas is one in which the particles are both non-repellent and non-attractive to one another (have no volume).
The general law of ideal gas can be applied here: PV is equal to nRT, where P is the gas pressure in atm.
V is the number of moles of the gas in a mole, and n is the volume of the gas in L. R is the universal gas constant. T is the temperature(Kelvin) of the gas.
If P and T are different values and n and V are constants, then
(P₁T₂) = (P₂T₁).
P₁ = 735 torr, T₁ = 29°C + 273 = 302 K,
P₂ = ??? torr, T₂ = 62°C + 273 = 335 K.
∴ P₂ = (P₁T₂)/(P₁) = (735 torr)(302 K)/(335 K) = 662.59 torr.
To know more about ideal gas law visit:
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