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4 years ago

A cone has a height of 36 cm and a volume of 588π cm3. What is its radius? ( The question I am working on..)

Mathematics

2 answers:

zhannawk [14.2K]4 years ago

6 0

Answer:

r = 7cm

Step-by-step explanation:

$h = 36 \\Volume = 588pi\\r = \\588pi = \frac{1}{3}pir^{2} 36\\Cross-multiply\\1764pi=36pir^{2} \\Divide-both-sides-of-the-equation-by-36pi\\r^{2} =\frac{1764pi}{36pi} \\r^{2} = 49\\Square -root-both-sides-of-the-equation.\\\sqrt{r^{2} } =\sqrt{49} \\r = 7$

Anvisha [2.4K]4 years ago

4 0

Steps:

Shape: Cone

Solved for radius

Height: 36 cm

Volume: 588 cm3

Formula= r=√3v/πh

R= Radius

H= Height

Description:

Using the formula r=√3v/πh, we have to calculate the radius. We know that the height is 36 and the volume of 588. We use the formula and get the answer. The answer we get is r≈3.95cm.

Answer: r≈3.95cm

Please mark brainliest

Hope this helps.

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A random sample of 49 measurements from one population had a sample mean of 15, with sample standard deviation 5. An independent

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Answer:

Comparing the p value with the significance level $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.

Step-by-step explanation:

$\bar X_{1}=15$ represent the mean for sample 1

$\bar X_{2}=18$ represent the mean for sample 2

$s_{1}=5$ represent the sample standard deviation for 1

$s_{f}=6$ represent the sample standard deviation for 2

$n_{1}=49$ sample size for the group 2

$n_{2}=64$ sample size for the group 2

$\alpha=0.01$ Significance level provided

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the difference in the population means, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}=0$

Alternative hypothesis: $\mu_{1} - \mu_{2}\neq 0$

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=49+64-2=111$

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$t=\frac{(15-18)-0}{\sqrt{\frac{5^2}{49}+\frac{6^2}{64}}}}=-2.897$