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aliya0001 [1]
3 years ago
11

If anyone can help me solve one of these equations, I will truly appreciate it!

Mathematics
1 answer:
bija089 [108]3 years ago
3 0
Photo math gal, it works
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Suppose a shipment of 120 electronic components contains 3 defective components. to determine whether the shipment should be​ ac
Likurg_2 [28]

For this problem, the most accurate is to use combinations


Because the order in which it was selected in the components does not matter to us, we use combinations

Then the combinations are nC_r = \frac{ n! }{r! (n-r)!}

n represents the amount of things you can choose and choose r from them


You need the probability that the 3 selected components at least one are defective.

That is the same as:

(1 - probability that no component of the selection is defective).

The probability that none of the 3 selected components are defective is:

P = \frac{_{117}C_3}{_{120}C_3}


Where _{117}C_3 is the number of ways to select 3 non-defective components from 117 non-defective components and _{120}C_3 is the number of ways to select 3 components from 120.

_{117}C_3 = 260130

_{120}C_3 = 280840


So:

P = \frac{260130}{280840} = 0.927


Finally, the probability that at least one of the selected components is defective is:


P = 1-0.927 = 0.0737

  P = 7.4%

3 0
4 years ago
10+3+(2×0.1)+(3×0.01)+(5×0.001) in word form?
charle [14.2K]
Simply add and multiply the numbers and you get 13.235
in word form that would be
13 and 2 tenths and 3 hundredths and 5 thousandths
8 0
3 years ago
What is the equation of line l?
inessss [21]
Y=-3/2L -2. At the Y axis, line L is at -2, so we add that as B or the Y intercept. We can see that the graph goes 2 over to the right and down three, which makes the slope negative and 3/2 (rise/run)
5 0
4 years ago
Solve the system.<br> x = y +2 <br> 3x = 6 (y + 2)
Zielflug [23.3K]

Answer:

(x , y)=(0 , -2)

Step-by-step explanation:

5 0
2 years ago
If two students from this college are selected at random, what is the probability that they are both males?
igor_vitrenko [27]

Answer:

P(A_1 and A_2) = P(A_1) *P(A_2)= 0.3*0.3 =0.09

Step-by-step explanation:

Assuming this problem :"Only 30% of the students in a certain liberal arts college are males. If two students from this college are selected at random, what is the probability that they are both males?"

Previous concepts

An independent event is an "event that has no connection to another event's chances of happening ". For this case we can assume that if one person is male and if we select another one the probability that this one would be male or female is totally indepedent from the first selection.

When we have two independent events let's say A and B and we want to find the probability that both events occurs at the same time we can use the following formula:

P(A and B) = P(A)*P(B)

Solution to the problem

We can define some notation:

A_1 first person selected is a male

A_2 second person selected is male

On this case we want the probability that both would be males. And we can express this like this on math terms:

P(A_1 and A_2)

For this case we can assume that the two events are independent. And in order to find the probability for two events independents events we just need to multiply the probabilities of each one like this:

P(A_1 and A_2) = P(A_1) *P(A_2)= 0.3*0.3 =0.09

5 0
3 years ago
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