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katen-ka-za [31]
3 years ago
10

What does how much mean

Mathematics
1 answer:
Gala2k [10]3 years ago
5 0
In this case, The amount of money she saved.
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Jeffery wants to save the same amount of money each week to buy a new bike. He needs $224.If he wants the bike in 14 weeks, how
a_sh-v [17]

Answer:

16 dollars per week

Step-by-step explanation:

Divide 224 by 14

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3 years ago
(PLZZZZ HELP ME its actually easy I am trying to check my work) Bob's family of three was driving to Washington D.C.. They were
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3 years ago
Which equations show you how to find 16-9?
Pie
The correct answer is B.
16-9=7
So, 7+9=16.

If we add to 9 only 1 (out of those 7) we have then 10, remaining 6.
9+1=10

Now, if to 10 we add the remaining 6 we will have the final 16.
10+6=16

16-9=7 <=> 9+7=16 <=> (9+1)+6=16
5 0
3 years ago
Harry collects data from a random sample of seventh-graders. Out of 25 respondents, 10 ride the bus home. Of the 150 seventh-gra
alekssr [168]

10/25=x/150

x=60

so 60 students

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7 0
3 years ago
Read 2 more answers
Evaluate the following pic
GREYUIT [131]

Answer:

1) \sqrt{1225}+\sqrt{1024}=67

2)  \sqrt[3]{-1331}=-11

3) Evaluating 2:p :: p:8 we get p=\pm 4

4) x^3+y^2+z \ when \ x=3, y=-2, x=-6 \ we \ get \ \mathbf{25}

5) \frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}=-6

Step-by-step explanation:

1) \sqrt{1225}+\sqrt{1024}

Prime factors of 1225 : 5x5x7x7

Prime factors of 1024: 2x2x2x2x2x2x2x2x2x2

\sqrt{1225}+\sqrt{1024}\\=\sqrt{5\times5\times7\times7}+\sqrt{2\times2\times2\times2\times2\times2\times2\times2\times2\times2}\\=\sqrt{5^2\times7^2}+\sqrt{2^2\times2^2\times2^2\times2^2\times2^2}\\=5\times7+(2\times2\times2\times2\times2)\\=35+32\\=67

\sqrt{1225}+\sqrt{1024}=67

2) \sqrt[3]{-1331}

We know that \sqrt[n]{-x}=-\sqrt[n]{x} \ ( \ if \ n \ is \ odd)

Applying radical rule:

\sqrt[3]{-1331}\\=-\sqrt[3]{1331} \\=-\sqrt[3]{11\times\11\times11}\\=-\sqrt[3]{11^3} \\Using \ \sqrt[n]{x^n}=x \\=-11

So, \sqrt[3]{-1331}=-11

3) 2:p :: p:8

It can be written as:

p*p=2*8\\p^2=16\\Taking \ square \ root \ on \ both \ sides\\\sqrt{p^2}=\sqrt{16}\\p=\pm 4

Evaluating 2:p :: p:8 we get p=\pm 4

4) x^3+y^2+z \ when \ x=3, y=-2, x=-6

Put value of x, y and z in equation and solve:

x^3+y^2+z \\=(3)^3+(-2)^2+(-6)\\=27+4-6\\=25

So, x^3+y^2+z \ when \ x=3, y=-2, x=-6 \ we \ get \ \mathbf{25}

5) \frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}

We know (-a)^n = (a)^n when n is even and (-a)^n = (-a)^n when n is odd

\frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}\\\\=\frac{1296\times-8\times 27}{46656}\\\\=\frac{-279936}{46656} \\\\=-6

So, \frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}=-6

8 0
2 years ago
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