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2 years ago

Is 5/16 smaller than 3/5

Mathematics

2 answers:

zheka24 [161]2 years ago

4 0

Yes 5/6 is smaller than 3/5

forsale [732]2 years ago

3 0

Answer:

YES

Step-by-step explanation:

first what i did is made them have common denominators. I made mine 80. so it changed them to 25/80 and 48/80 now the answer is a lot more clear. now you can do 25/80<48/80

hope it helps

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The manufacturer of hardness testing equipment uses steel-ball indenters to penetrate metal that is being tested. However, the

kumpel [21]

Answer:

Check the explanation

Step-by-step explanation:

Let X denotes steel ball and Y denotes diamond

$\bar{x_1}$ = 1/9( 50+57+......+51+53)

=530/9

=58.89

$\bar{x_2}$ = 1/9( 52+ 56+....+ 51+ 56)

=543/9

=60.33

difference = d =(60.33- 58.89)

=1.44

$s^2=1/n\sum xi^2 - n/(n-1)\bar{x}^2$

s12 = 1/9( 502+572+......+512+532) -9/8 (58.89)2

=31686/8 - 9/8( 3468.03)

=3960.75 - 3901.53

=59.22

s1 = 7.69

s22 = 1/9( 522+ 562+....+ 512+ 562) -9/8 (60.33)2

=33295/8 - 9/8 (3640.11)

=4161.875 - 4095.12

=66.75

s2 =8.17

sample standard deviation for difference is

s= $\sqrt{[(n1-1)s_1^2+ (n2-1)s_2^2]/(n1+n2-2)}$

= $\sqrt{[(9-1)*59.22+ (9-1)*66.75]/(9+9-2)}$

= $\sqrt{1007.76/16}$

=7.93

sd = $s*\sqrt{(1/n1)+(1/n2)}$

= $7.93*\sqrt{(1/9)+(1/9)}$

=7.93* 0.47

=3.74

For 95% confidence level $Z (\alpha /2)$ =1.96

confidence interval is

$d\pm Z(\alpha /2)*s_d$

=(1.44 - 1.96* 3.75 , 1.44+1.96* 3.75)

=(1.44 - 7.35 , 1.44 + 7.35)

=(-2.31, 8.79)

There is sufficient evidence to conclude that the two indenters produce different hardness readings.

3 0

3 years ago

Some help please? Which polynomial represents the difference below?

Helga [31]

So the right answer is of option D.

Look at the attached picture⤴

Hope it will help u...

4 0

2 years ago

Read 2 more answers

The Marshall Island goby, the world's smallest fish, measures .47 inch. The striped bass, an American sport fish, is about 25.5

OLEGan [10]

150 inches because i say it is because i just need the points to ask another question

6 0

2 years ago

Read 2 more answers

Solve for x A)9 B)33 C)45 D)62

sattari [20]

Answer:

A) 9

Step-by-step explanation:

R=7x+17

S=4x-6

Q=180-110=70

4x-6+7x+17+70=180
11x+81=190
11x=180-81
11x=99
x=99/11
x=9

3 0

3 years ago

HELP ME!!!!!!

sdas [7]

Answer:

A. Minimum = 54, Q1= 69.5, Median = 75, Q3= 106, Maximum = 183

Step-by-step explanation:

Arranging the data set in order from least to greastest we get:

54, 68, 71, 72, 75, 84, 104, 108, 183

From this, we can see that the minimum value is 54 and the maximum value is 183.

Taking a number off one by one on each side of the data set gives the median. In the middle lies 75, so that is our median

To find quartile ranges, split the data set into two where the median lies, then, find the median of those two data sets. The medians will be the values of the upper (Q3) and lower quartiles (Q1).

Q1: 54, 68, 71, 72

68 + 71 = 139
139 ÷ 2 = 69.5

-----

Q3: 84, 104, 108, 183

104 + 108 = 212

212 ÷ 2 = 106

Option A is the only answer with all of these values, therefore, it is the answer.

hope this helps!

3 0

2 years ago