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4 years ago

Which two points satisfy y = -x2 + 2x + 4 and x + y = 4?

Mathematics

1 answer:

r-ruslan [8.4K]4 years ago

8 0

Y=4-x
0= -x^2 + 3x
x=0 or 3
so y = 4-0 or y= 4-3
y=4 or 1

The two points are:
(0,4) and (3,1)

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Need help with this??? Please!!!

Radda [10]

Answer:

the first option

Step-by-step explanation:

(f-g)(x) simply means to subtract both expressions. really literally.

and we go through it power by power of x.

the highest power/exponent of x is 3 (x³). only f(x) has one.

so, -7x³ is the first part of f-g.

next is x².

11x² - 6x² = 5x², which is the second part of f-g.

next is x.

-8x - (-14x) = -8x + 14x = 6x, which is the third part of f-g.

next is x⁰ (in other words, no x, just a constant).

4 - (-3) = 4 + 3 = 7, which is the 4th part of f-g.

we have no x to the power of -1 or -2, so we have -3

0 - (-4x‐³) = 4x‐³, which is the last part of f-g.

so, it is clearly the first answer option.

3 0

3 years ago

PLS HELP I NEED THIS AND QUICK I need the problem to look like how it looks but solved or something >:(

pochemuha

Answer:

let me know if you cant read it my camera on my laptop is kinda trash

3 0

3 years ago

Read 2 more answers

I will give brainliest to the fastest answer and correct!

Marizza181 [45]

Answer:

I guess A is the correct answer.

6 0

2 years ago

Can someone pls explain how did he got this answer? I did not get 7 in my calculator. Pls thank u

iren2701 [21]

Answer:

You square 44 and 31 but you have two square cot². This is your error.

That's why you are getting wrong answer or you are not getting 7 in your calculator

8 0

3 years ago

If you were to flip a coin 10 times, what is the probability that it will land on heads exactly 7 out of 10 times?

bezimeni [28]

Answer:

The probability of flipping a coin 10 times and it landing on heads exactly seven times is about 0.1172 or 11.72%.

Step-by-step explanation:

We can use basic binomial distribution, which is given by the formula:

$\displaystyle P(x) = {n \choose x}p^xq^{n-x}$

Where n represent the number of trials, x represent the number of successes desired, p represent the chance of success, and q represent the chance of failure.

Since we are flipping a coin 10 times, we are conducting 10 trials. So, n = 10.

We want to probability that it lands on heads exactly 7 out of 10 times. So, the number of desired successes x is 7.

The probability of success p is 1/2.

And the probability of failure q is also 1/2.

Substituting:

$\displaystyle P(7)={10 \choose 7}\left(\frac{1}{2}\right)^7\left(\frac{1}{2}\right)^3=120\left(\frac{1}{2}\right)^{10}=\frac{120}{1024}=\frac{15}{128}\approx0.1172$

The probability of flipping a coin 10 times and it landing on heads exactly seven times is about 0.1172 or 11.72%.

8 0

3 years ago