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lesantik [10]
3 years ago
6

Real world equation that can be modeled by the equation y=1/20x

Mathematics
1 answer:
fomenos3 years ago
8 0
Nick has to pay 5 cents in tax (5%) for every dollar he spends buying pizza. How much money does he have to pay in tax? Since 5=1/20*100, that means that if x is the amount of dollars he spends buying pizza, he has to divide that by 20 to get 5% of that amount and therefore the amount of tax he has to pay
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What are three main ways in Whitehall organisms interact
Degger [83]

Answer:

http://www.classzone.com/science_book/mls_grade6_FL/540_547.pdf

Step-by-step explanation:


7 0
3 years ago
What is a equivalent fraction and decimal to 3 ones and 7 hundreths
nasty-shy [4]
3 ones = 3
7 hundredths = 7/100

So equivalent fraction is 3 7/100 or 307/100.
Equivalent decimal is: 3.07
4 0
3 years ago
Read 2 more answers
Given tan theta =9, use trigonometric identities to find the exact value of each of the following:_______
Ludmilka [50]

Answer:

(a)\ \sec^2(\theta) = 82

(b)\ \cot(\theta) = \frac{1}{9}

(c)\ \cot(\frac{\pi}{2} - \theta) = 9

(d)\ \csc^2(\theta) = \frac{82}{81}

Step-by-step explanation:

Given

\tan(\theta) = 9

Required

Solve (a) to (d)

Using tan formula, we have:

\tan(\theta) = \frac{Opposite}{Adjacent}

This gives:

\frac{Opposite}{Adjacent} = 9

Rewrite as:

\frac{Opposite}{Adjacent} = \frac{9}{1}

Using a unit ratio;

Opposite = 9; Adjacent = 1

Using Pythagoras theorem, we have:

Hypotenuse^2 = Opposite^2 + Adjacent^2

Hypotenuse^2 = 9^2 + 1^2

Hypotenuse^2 = 81 + 1

Hypotenuse^2 = 82

Take square roots of both sides

Hypotenuse =\sqrt{82}

So, we have:

Opposite = 9; Adjacent = 1

Hypotenuse =\sqrt{82}

Solving (a):

\sec^2(\theta)

This is calculated as:

\sec^2(\theta) = (\sec(\theta))^2

\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2

Where:

\cos(\theta) = \frac{Adjacent}{Hypotenuse}

\cos(\theta) = \frac{1}{\sqrt{82}}

So:

\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2

\sec^2(\theta) = (\frac{1}{\frac{1}{\sqrt{82}}})^2

\sec^2(\theta) = (\sqrt{82})^2

\sec^2(\theta) = 82

Solving (b):

\cot(\theta)

This is calculated as:

\cot(\theta) = \frac{1}{\tan(\theta)}

Where:

\tan(\theta) = 9 ---- given

So:

\cot(\theta) = \frac{1}{\tan(\theta)}

\cot(\theta) = \frac{1}{9}

Solving (c):

\cot(\frac{\pi}{2} - \theta)

In trigonometry:

\cot(\frac{\pi}{2} - \theta) = \tan(\theta)

Hence:

\cot(\frac{\pi}{2} - \theta) = 9

Solving (d):

\csc^2(\theta)

This is calculated as:

\csc^2(\theta) = (\csc(\theta))^2

\csc^2(\theta) = (\frac{1}{\sin(\theta)})^2

Where:

\sin(\theta) = \frac{Opposite}{Hypotenuse}

\sin(\theta) = \frac{9}{\sqrt{82}}

So:

\csc^2(\theta) = (\frac{1}{\frac{9}{\sqrt{82}}})^2

\csc^2(\theta) = (\frac{\sqrt{82}}{9})^2

\csc^2(\theta) = \frac{82}{81}

4 0
3 years ago
Which is the best estimate for the percent equivalent of 7/15
zzz [600]
An estimate for the percent equivalent of 7/15 is 46% i think
7 0
3 years ago
Read 2 more answers
The sides of a square are five to the power of two fifths inches long. How is that written in radical form?
Evgen [1.6K]
Remember
x^ \frac{m}{n}= \sqrt[n]{x^m}
so
5^ \frac{2}{5}= \sqrt[5]{5^2}= \sqrt[5]{25}

5 0
3 years ago
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