Put them into y=mx+b
y=1/3x -1
y=2/3x-4
Graph them. Where they touch is your answer. No touch? No solution. Same line? Infinite solutions.
Second set: Same thing.
Solution to first set is (9,2)
Actually you can't solve this. There is no solutions.
We need the height of the cone
what we do is we know that when height is 10, V=something, so solve for the diameter is at that point and compare it to 24, the full height
sorry if confusing
V=(1/3)hpir^2
when h=10
160pi/3=1/3(10)pir^2
ties 3 both sides
160pi=10pir^2
divide by 10pi
16=r^2
sqrt both sides
r=4
at that point, the radius is 4
the real radius of the ful is 24/2=12
4/12=1/3
it is 1/3 full
if 1/3=160pi/3cm
2/3=320pi/3cm^3
needs 320pi/3 cm^3
47-(-38)
47+38
85
hope this helps!
Step-by-step explanation: When an equation has a squared term in it
such as x² - 2x - 63 = 0, it's called a polynomial equation.
The rule for solving a polynomial equation is
to first set it equal to 0, them factor.
Since this equation is already set equal to 0, we can factor the left side.
To factor x² - 2x - 63, look for factors of -63 that add to -2.
In this case, these factors are -9 and +7.
So we have (x - 9)(x + 7) = 0.
When two terms are multiplying together to equal 0,
either one term or the other must equal 0.
So x - 9 = 0 or x + 7 = 0.
Solving for x in each equation, we get x = 9 or x = -7.
So this equation has two solutions and we write out answer
in set notation which looks like this {9, -7}.
