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4 years ago

What occurs when potassium reacts with chlorine to form potassium chloride?

1 answer:

7 0

Basically since potassium chloride is an ionic compound as it consists of a metal and a nonmetal, the potassium atom will donate one of its valence electrons to chlorine that will accept it and as a result produce oppositely charged ions, where the K + ion and the Cl - ion will attract forming an ionic bond. The compound that results is potassium chloride.

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Why are supergiant so bright?

Yuliya22 [10]

Because supergiants are so massive, the core temperature gets much hotter than in giants, so supergiants can fuse elements heavier than hydrogen and helium. But to support their tremendous mass, supergiants burn up their fuel much more quickly.

5 0

3 years ago

Read 2 more answers

If a sample of gas at constant temperature has its pressure doubled, what will happen to its volume?

kozerog [31]

Answer:

it'll halve

Explanation:

the gas is compressed with twice the pressure. The volume will be halved.

im certain

6 0

3 years ago

What is the value for the kinetic energyfor a n = 2 Bohr orbit electron in Joules?

Vladimir [108]

Answer:

K.E. = 5.4362 × 10⁻¹⁹ J

Explanation:

The expression for Bohr velocity is:

$v=\frac{Ze^2}{2 \epsilon_0\times n\times h}$

Applying values for hydrogen atom,

Z = 1

Mass of the electron ( $m_e$ ) is 9.1093×10⁻³¹ kg

Charge of electron (e) is 1.60217662 × 10⁻¹⁹ C

$\epsilon_0$ = 8.854×10⁻¹² C² N⁻¹ m⁻²

h is Plank's constant having value = 6.626×10⁻³⁴ m² kg / s

We get that:

$v=\frac {2.185\times 10^6}{n}\ m/s$

Given, n = 2

So,

$v=\frac {2.185\times 10^6}{2}\ m/s$

$v=1.0925\times 10^6\ m/s$

Kinetic energy is:

$K.E.=\frac {1}{2}\times mv^2$

So,

$K.E.=\frac {1}{2}\times 9.1093\times 10^{-31}\times ({1.0925\times 10^6})^2$

K.E. = 5.4362 × 10⁻¹⁹ J

3 0

3 years ago

A 59.1 sample of aluminum is put into a calorimeter (see sketch at right) that contains of water. The aluminum sample starts off

Gemiola [76]

Answer:

Specific heat capacity of aluminium is 0,863 J/g°C

Explanation:

Values: 250g of water, aluminum sample starts off at 91.3°C, water starts off at 16.0°C, temperature of the water stops changing it's 19.5°C

In this problem, the heat produced for the aluminium is the same consumed by water. The heat consumed by water is:

Q = C×m×ΔT (1)

Where C is specific heat of water (4,184J/g°C), m is mass of water (250,0g) and ΔT is change in temperature of water (19,5°C-16,0°C = 3,5°C)

Replacing:

Q = 4,184J/g°C×250,0g×3,5°C

Q = 3661 J

Using (1), it is possible to obtain specific heat of aluminium, thus:

Q / (m×ΔT) = C

Where Q is heat (3661J), m is mass (59,1g) and ΔT is change in temperature (91,3°C - 19,5°C( = 71,8°C

Replacing:

3661J / (59,1g×71,8°C) = C

C = 0,863 J/g°C

I hope it helps!

4 0

4 years ago

Why do you think lone pairs of electrons create greater repulsion when located near other

Sedaia [141]

When there are lone pairs on the valence shell of the central atom in a molecule, the bond angle is decreased.

The shape of molecules depend on the number of electron pairs on the valence shell of the molecules. These electron pairs could be lone pairs or bond pairs. Lone pairs occupy more space around the central atom since it is attracted to only one nucleus compared to bond pairs which are attracted to two nuclei.

When lone pairs are present on the central atom in a molecule, they tend to "squeeze" the molecule thereby decreasing the bond angle in the molecule. Hence, presence of one or more lone pairs of electrons make the bond angles get smaller.

Learn more: brainly.com/question/10079361

5 0

3 years ago