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____ [38]
3 years ago
5

BRAINLIEST AWARD!! Why is potassium nitrate a solute in a .3M potassium nitrate solution? Please explain:D

Chemistry
1 answer:
Bond [772]3 years ago
8 0

Answer:

In a .3M KNO3 solution, the KNO3 is dissolved in water. Water is the solvent and KNO3 is the solute, because the solute is what is dissolved. Also, all potassium compounds and nitrate compounds are soluble, so you know that KNO3 dissociates into K+ and NO3- in water.

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garik1379 [7]

Answer: C

Explanation:

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ehidna [41]
The answer is letter C.

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2 years ago
Which of the following [H+] values describes the most basic (alkaline) solution?
Aleks04 [339]
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4 0
3 years ago
Which of the following 0.820 M solutions would have the greatest colligative effect?
eimsori [14]

Answer:

K3PO4

Explanation:

Recall that colligative properties depends on the number of particles present. The greater the number of particles present, the greater the degree of colligative properties of the solution. Let us look at each option individually;

SrCr2O7-------> Sr^2+ + Cr2O7^2- ( 2 particles)

C4H11N (not ionic in nature hence it can not dissociate into ions)

K3PO4-------> 3K^+ + PO4^3- (4 particles)

Rb2CO3-------> 2Rb^+ + CO3^2- (3 particles)

Hence K3PO4 has the greatest number of particles and will display the greatest colligative effect.

8 0
3 years ago
2. A quantity of 1.922g of methanol (CH3OH) was burned in a constant-volume
Cerrena [4.2K]
Mass of methanol (CH3OH) = 1.922 g
Change in Temperature (t) = 4.20°C
Heat capacity of the bomb plus water = 10.4 KJ/oC
The heat absorbed by the bomb and water is equal to the product of the heat capacity and the temperature change.
Let’s assume that no heat is lost to the surroundings. First, let’s calculate the heat changes in the calorimeter. This is calculated using the formula shown below:
qcal = Ccalt
Where, qcal = heat of reaction
Ccal = heat capacity of calorimeter
t = change in temperature of the sample
Now, let’s calculate qcal:
qcal = (10.4 kJ/°C)(4.20°C)
= 43.68 kJ
Always qsys = qcal + qrxn = 0,
qrxn = -43.68 kJ
The heat change of the reaction is - 43.68 kJ which is the heat released by the combustion of 1.922 g of CH3OH. Therefore, the conversion factor is:
5 0
3 years ago
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