<h3>
Answer:</h3>
5.89 × 10^23 molecules of F₂
<h3>
Explanation:</h3>
The equation for the reaction between fluorine (F₂) and ammonia (NH₃) is given by;
5F₂ + 2NH₃ → N₂F₄ + 6 HF
We are given 66.6 g NH₃
We are required to determine the number of fluorine molecules
<h3>Step 1: Moles of Ammonia </h3>
Moles = Mass ÷ Molar mass
Molar mass of ammonia = 17.031 g/mol
Moles of NH₃ = 66.6 g ÷ 17.031 g/mol
= 3.911 moles
<h3>Step 2: Moles of Fluorine </h3>
From the equation 5 moles of Fluorine reacts with 2 moles of ammonia
Therefore,
Moles of fluorine = Moles of Ammonia × 5/2
= 3.911 moles × 5/2
= 9.778 moles
<h3>Step 3: Number of molecules of fluorine </h3>
We know that 1 mole of a compound contains number of molecules equivalent to the Avogadro's number, 6.022 × 10^23 molecules
Therefore;
1 mole of F₂ = 6.022 × 10^23 molecules
Thus,
9.778 moles of F₂ = 9.778 moles × 6.022 × 10^23 molecules/mole
= 5.89 × 10^23 molecules
Therefore, the number of fluorine molecules needed is 5.89 × 10^23 molecules
No they are not, as climate is long term conditions for an area while weather is temporary
Answer:
The process of photosynthesis occurs when green plants use the energy of light to convert carbon dioxide (CO2) and water (H2O) into carbohydrates. Light energy is absorbed by chlorophyll, a photosynthetic pigment of the plant, while air containing carbon dioxide and oxygen enters the plant through the leaf stomata.
Answer:
d. decomposition
Explanation:
decomposition reaction is a reaction in which a compound breaks down into 2 or more substances.
the general form is: AB → A + B
4300 meters = approximately 14107.61 feet.
Boiling point is 212 degrees Fahrenheit at sea level.
(Each 500 feet increase in elevation will be lowered by approximately 1 degrees Fahrenheit)
14107.61 feet divided by 500 feet = <span>28.21522
So the boiling point would be lowered by about 28 degrees Fahrenheit at 4300 meters above sea level. Which will make your new boiling point 184 degrees Fahrenheit instead of 212.
184 degrees Fahrenheit = 84.4 degrees Celcius</span>
