Answer:
2 moles
Explanation:
Given data:
Moles of water produced =?
Moles of propane = 0.5 mol
Solution:
Chemical equation:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
Now we will compare the moles of propane and C₃H₈.
C₃H₈ : H₂O
1 : 4
0.5 : 4/1×0.5 = 2 mol
Thus 2 mole of water are produced from 0.5 moles of propane.
E. co and n2Effusion is the process where gas escapes through a hole. Gases with a lower molecular mass effuse more speedy than gases with a higher molecular mass. R<span>elative rates of effusion is related to the molecular mass.
a) M(N</span>₂)/M(O₂) = 28/32 = 0,875
b) M(N₂O)/M(NO₂) = 44/46 = 0,956
c) M(CO)/M(CO₂) = 28/44 = 0,636
d) M(NO₂)/M(N₂O₂) = 44/58= 0,758
e) M(CO)/M(N₂) = 28/28 = 1, <span>CO and N</span>₂ <span>have iexact molecular masses and will effuse at nearly identical rates.</span>
Answer:
Explanation:
Heat of combustion of = -1366.8 kJ/mol
Heat of formation of = -393.5 kJ/mol
Heat of formation of = -285.8 kJ/mol
The reaction is
Assuming is the standard enthalpy of formation of ethanol
The standard enthalpy of formation of ethanol is .
The number of protons. hope this helps. :)
dragonflies<span>, </span>grasshoppers<span> and cockroaches.</span>