3 years ago

Which has the higher percentage of aluminum, Al2O, or Al(NO3)3

Chemistry

1 answer:

Rzqust [24]3 years ago

8 0

Al₂O has a higher percentage of aluminium.

Explanation:

To solve this problem, we have to compare the molar mass of the aluminium in each compound to one another as percentage of the whole compound:

Molar mass of Al₂O = 2(27) + 16 = 70g/mol

Molar mass of Al(NO₃)₃ = 27 + 3[14 + 3(16)] = 213g/mol

Percentage by mass of Al in Al₂O = $\frac{2x27}{70}$ x 100 = 77%

Percentage by mass of Al in Al(NO₃)₃ = $\frac{27}{213}$ x 100 = 12.7%

Al₂O has a higher percentage of aluminium.

learn more:

Molar mass brainly.com/question/2861244

#learnwithBrainly

You might be interested in

a block of iron has the dimensions of 3.00 cm x 3.00 cm x 3.00 cm. it has a mass of 213 g. what is its density? a. 638 g/cm3 b.

Juliette [100K]

Volume = 3 cm × 3cm × 3cm
= 27 cm ³

Mass = 213 g

Density = $\frac{MASS}{VOLUME}$

= <span> $\frac{213 g}{27 cm ^{3} }$
</span>
<span> = 7.89 g / cm³

Thus answer is D.</span>

8 0

3 years ago

Read 2 more answers

calculate the number of moles of gas that occupy a 3.45L container at a pressure of 1.48 atm and a temperature of 45.6 Celsius

Otrada [13]

Answer:

There are 0,2 moles of gas that ocuppy the container.

Explanation:

We apply the formula of the ideal gases, we clear n (number of moles); we use the ideal gas constant R = 0.082 l atm / K mol. Firs we convert the unit of temperature in Celsius into Kelvin:

0°C= 273 K ------> 45,6 °C= 273 + 45, 6= 318, 6 K

PV= nRT ---> n= PV/RT

n= 1,48 atm x 3,45 L /0.082 l atm / K mol x 318,6 K

n= 0,195443479 mol

8 0

3 years ago

Two processes are described below:

UNO [17]

Answer:

i would say D i just did this but i kinda forgot so sorry if im wrong or A

Explanation:

4 0