Answer:
δ N2(g) = 1.1825 g/L
Explanation:
- δ ≡ m/v
- Mw N2(g) = 28.0134 g/mol
ideal gas:
∴ P = (837 torr)×( atm/760 torr) = 1.1013 atm
∴ T = 45.0 °C + 273.15 = 318.15 K
∴ R = 0.082 atm.L/K.mol
⇒ n/V = P/R.T
⇒ n/V = (1.1013 atm) / ((0.082 atm.L/K.mol)(318.15 k))
⇒ n/V = 0.0422 mol/L
⇒ δ N2(g) = (0.042 mol/L)×(28.0134 g/mol) = 1.1825 g/L
Explanation:
To remove the salt from the oil, I will add water to dissolve the salt from it.
Oil is an organic molecule that is non-polar
Salt is polar ionic compound
Salt will not dissolve in the oil.
- Take the mixture.
- Add water to it.
- Water and oil are immiscible
- Shake the new heterogeneous mixture vigorously.
- leave to settle.
- Oil will come on top of the water.
- You can skim off the oil layer on top.
- Then heat the water and salt solution.
- This leaves the oil behind.
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