Its FeSO3 or iron(iii)sulfite = Fe2(SO3)3
2.565L
Explanation:
- Charles law states that the volume of an ideal gas at constant pressure is directly proportional to the absolute temperature.V/T=K
V1/T1=V2/T2
Unit of Kelvin = 273.15
- To get the absolute temperature, we need to convert the degree celsius temperature to kelvin.
T1= 22+273.15= 295.15 K
T2 = 71+273.15= 344.15 K
V1 = 2.20 L
V2 =?
2.20/295.15=V2/344.15
0.00745 x 344.15 = 2.565 L
Hence, 2.565 L is the new volume of the balloon.
The last step in performing a titration is <span>determining the concentration of an unknown base. So the answer to your question is letter B. The concentration maybe either an acid or base. The other choices are the earlier procedures in performing titration.</span>
Answer: The standard enthalpy change for this reaction is -116 kJ
Explanation:
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The given chemical reaction is,


Now we have to determine the value of
for the following reaction i.e,

According to the Hess’s law, if we reverse the reaction then the
will change its sign and if we half the reaction, then the
So, the value
for the reaction will be:

Hence, the standard enthalpy change for this reaction is -116 kJ
Answer:
Here's what I find.
Explanation:
a. Structure
Acebutolol is a secondary amine (basic). It forms a substituted ammonium salt when treated with hydrochloric acid.
The structure of the salt is shown below, with a red arrow pointing toward the positive charge on the N atom.
b. Solubility
The formula of acebutolol is C₁₈H₂₈N₂O₄.
The amide, acetyl, and ether groups confer little solubility to the molecule.
The alcohol and secondary amine do confer some solubility, because they can donate and accept hydrogen bonds.
However, they can each overcome the hydrophobic properties of only three to five carbons, and acebutolol has 18 of them.
The free amine would be preferentially soluble in lipid material (fats)
The protonated amine is ionic and therefore much more soluble in aqueous media (e.g., blood).
c. Marketing
The drug must be delivered to the tissues of the heart, where it blocks the effects of adrenalin. The best way to do this is through the blood, so acebutolol is marketed as the hydrochloride salt.