The minimum volume of 0.2M sodium sulfide that will precipitate out aluminum from 50.0 mL, 0.25 M aluminum nitrate would be 0.094 L or 94 mL
<h3>Stoichiometric calculation</h3>
From the equation of the reaction:
Mole ratio of Na2S and Al(NO3)3 = 3:2
Mole of 50.0 mL, 0.25 M Al(NO3)3 = 50/1000 x 0.25
= 0.0125 mole
Equivalent mole of Na2S = 3/2 x 0.0125
= 0.0188 mole
Volume of 0.2M, 0.0188 mole Na2S = 0.0188/0.2
= 0.094 L or 94 mL
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Answer:
H2SO4 + 2NaOH ---> Na2SO4 + 2H2O
Explanation:
H2SO4 + NaOH ---> Na2SO4 + H2O
Na1 ---> 2Na
H2SO4 + 2NaOH ---> Na2SO4 + H2O
2H + 2H = 4H ----> 2H
H2SO4 + 2NaOH ---> Na2SO4 + 2H2O
4O + 2O -----> 4O + 2O
sodium hydroxide (NAOH) a.k.a causic soda commonly used in labs.
- MOLAR MASS of naoh is 39.997 g/mol.
- It is dry hard brittle, white stocks in large fused opaque white-stone like masses having a dense crystalline fracture in small pellets/flakes.
- it is very delinquent and one of the strongest base , acts as a saponifying agent which is used in industrial purposes.
- It is an important industrial chemical as it is used on its own and is also used as a raw material in the production of other chemicals. The basis for the production of sodium hydroxide is the electrolysis of brine.
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Answer:
C
Explanation:
It's used to mesure energy used in ectothermic and endothermic reaction s
4 3 4 111.6 3 r = 111.6 cm3<span> = (3.1416)r3 r= 3 = 2.987 cm V= 3 3 4(3.1416) 3A ... with it absent. </span>density<span> =</span>mass<span> 28.4 g rock = = 2.76 g/mL = 2.76 g/</span>cm3<span> volume 44.1 ... can be found using dimensional analysis. ethanol </span>mass<span> = </span>25<span> L gasohol 1000 mL ..... 100.00 g solution = 9.95 103 g solution 1 kg sucrose </span>10.05 g<span>sucrose 53.</span>
