Scot would have 4 football cards..
Not 100% sure
Sorry =,(
Using the speed - distance relationship, the time left before the appointed time is 27 minutes.
<u>Recall</u><u> </u><u>:</u>
<u>At</u><u> </u><u>10mph</u><u> </u><u>:</u>
- Distance = 10 × (t + 3) = 10t + 30 - - - (1)
<u>At</u><u> </u><u>12</u><u> </u><u>mph</u><u> </u><u>:</u>
- Distance = 12 × (t - 2) = 12t - 24 - - - - (2)
<em>Equate</em><em> </em><em>(</em><em>1</em><em>)</em><em> </em><em>and</em><em> </em><em>(</em><em>2</em><em>)</em><em> </em><em>:</em>
10t + 30 = 12t - 24
<em>Collect</em><em> </em><em>like</em><em> </em><em>terms</em><em> </em>
10t - 12t = - 24 - 30
-2t = - 54
<em>Divide</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>by</em><em> </em><em>-</em><em> </em><em>2</em>
t = 54 / 2
t = 27
Hence, the time left before the appointed time is 27 minutes.
Learn more : brainly.com/question/25669152
3pi r 2 603.43 is the answer
Answer:
The average of -2.5, 5.2, 1.7, and -0.8 is <u>0.9</u>
Step-by-step explanation:
You are taking the mean of all the values
So you would add -2.5, 5.2, 1.7, and -0.8 all together
This gives you 3.6
Then you would divide by the number of numbers per se,
Which would give you the answer: 0.9
X = # of posters, y = total cost
y = 2x + 250
y = 1000
1000 = 2x + 250
1000 - 250 = 2x
750 = 2x
750/2 = x
375 = x....so 375 posters can be printed
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y = total cost, x = # of miles
y = 3x + 3
y = 117
117 = 3x + 3
117 - 3 = 3x
114 = 3x
114/3 = x
38 = x.....so the car was towed 38 miles
